Tangent Properties and Semicircles

Tangent Properties and Semicircles

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explores a geometric problem involving a 40-75-85 triangle. It explains how to find the maximum area of a semicircle that can fit within the triangle by using one of its sides as the diameter. The tutorial covers the construction of similar triangles, the calculation of the semicircle's radius, and the logic behind maximizing the semicircle's size. The process involves understanding the relationships between the triangle's sides and the semicircle's radius, using geometric principles and calculations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common factor used to simplify the 40-75-85 triangle?

6

5

4

3

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the center of the semicircle not the same as the center of AC?

Because the semicircle would be too large

Because the semicircle would extend outside the triangle

Because the semicircle would be too small

Because the semicircle would not touch the triangle

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between triangle AOP and triangle ABC?

They are congruent

They are similar

They are unrelated

They are identical

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which side of the small triangle corresponds to the hypotenuse of the large triangle?

OP

AP

AO

AB

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the calculated radius of the semicircle using the 40 side?

24.5

22.0

20.5

18.75

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which side of the triangle should be used to get the largest semicircle?

The middle side

Any side

The shortest side

The longest side

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What property of the tangent is used to determine the semicircle's placement?

It is longer than the radius

It is perpendicular to the radius

It is parallel to the radius

It is equal to the radius

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