Chpt 9 quiz part 1 (problems 2 and 4)

At a hospital called "Quick Care," the average wait time for non-emergency patients is 15 minutes with a deviation of 3.5 minutes after surveying 500 patients. At another hospital called "Slow Care," the average wait time after surveying 300 patients was 10 minutes with a deviation of 4.0 minutes. Test the claim that the average wait time for "Slow Care" is less than the average wait time for "Quick Care" using a 0.05 significance level. What is the t-value, P-value, and conclusion of this t-test?

• t-value: 15.811, P-value: 1.11e-45; Fail to reject the null hypothesis

• t-value: 2.01, P-value: 0.05; Fail to reject the null hypothesis

• t-value: 15.811, P-value: 1.11e-45; Reject the null hypothesis

• t-value: 2.01, P-value: 0.05; Reject the null hypothesis

Tags

CCSS.HSS.ID.A.4

At a hospital called "Fast Track," the average wait time for non-emergency patients is 20 minutes with a deviation of 5.0 minutes after surveying 600 patients. At another hospital called "Slow Lane," the average wait time after surveying 350 patients was 18 minutes with a deviation of 6.0 minutes. Test the claim that the average wait time for "Slow Lane" is less than the average wait time for "Fast Track" using a 0.05 significance level. What is the t-value, P-value, and conclusion of this t-test?

• t-value: 4.472, P-value: 4.34e-06; Fail to reject the null hypothesis

• t-value: 3.01, P-value: 0.04; Fail to reject the null hypothesis

• t-value: 4.472, P-value: 4.34e-06; Reject the null hypothesis

• t-value: 3.01, P-value: 0.04; Reject the null hypothesis

Tags

CCSS.HSS.ID.A.4

At a hospital called "Speedy Care," the average wait time for non-emergency patients is 25 minutes with a deviation of 4.5 minutes after surveying 700 patients. At another hospital called "Turtle Care," the average wait time after surveying 400 patients was 22 minutes with a deviation of 5.5 minutes. Test the claim that the average wait time for "Turtle Care" is less than the average wait time for "Speedy Care" using a 0.05 significance level. What is the t-value, P-value, and conclusion of this t-test?

• t-value: 8.485, P-value: 1.23e-16; Fail to reject the null hypothesis

• t-value: 8.485, P-value: 1.23e-16; Reject the null hypothesis

• t-value: 4.01, P-value: 0.03; Fail to reject the null hypothesis

• t-value: 4.01, P-value: 0.03; Reject the null hypothesis

Tags

CCSS.HSS.ID.A.4

At a hospital called "Express Care," the average wait time for non-emergency patients is 30 minutes with a deviation of 6.0 minutes after surveying 800 patients. At another hospital called "Leisure Care," the average wait time after surveying 500 patients was 25 minutes with a deviation of 7.0 minutes. Test the claim that the average wait time for "Leisure Care" is less than the average wait time for "Express Care" using a 0.05 significance level. What is the t-value, P-value, and conclusion of this t-test?

• t-value: 9.486, P-value: 2.34e-20; Fail to reject the null hypothesis

• t-value: 5.01, P-value: 0.02; Fail to reject the null hypothesis

• t-value: 9.486, P-value: 2.34e-20; Reject the null hypothesis

• t-value: 5.01, P-value: 0.02; Reject the null hypothesis

Tags

CCSS.HSS.ID.A.4

At a university, 50 students were surveyed about their preference for online classes. 30 of them prefer online classes. 60 students were surveyed about their preference for in-person classes and 40 said that they prefer in-person classes. Use a 0.05 hypothesis test to test the claim that the percent of students who prefer online classes is the same as the percent of students who prefer in-person classes.

• Z-value: -0.724, P-value: 0.46922, Fail to reject the null hypothesis, Does not support the claim

• Z-value: -0.224, P-value: 0.47922, Fail to reject the null hypothesis, Does not support the claim

• Z-value: -1.224, P-value: 0.45922, Reject the null hypothesis, Supports the claim

• Z-value: 0.276, P-value: 0.48922, Fail to reject the null hypothesis, Does not support the claim

At a hospital, 47 nurses were surveyed about their satisfaction with night shifts. 32 of them are satisfied with night shifts. 53 nurses were surveyed about their satisfaction with day shifts and 33 said that they are satisfied with day shifts. Use a 0.05 hypothesis test to test the claim that the percent of nurses who are satisfied with night shifts is the same as the percent of nurses who are satisfied with day shifts.

• Z-value: 1.609, P-value: 0.56246, Fail to reject the null hypothesis, Does not support the claim

• Z-value: 1.109, P-value: 0.55246, Fail to reject the null hypothesis, Does not support the claim

• Z-value: 0.109, P-value: 0.53246, Reject the null hypothesis, Supports the claim

• Z-value: 0.609, P-value: 0.54246, Fail to reject the null hypothesis, Does not support the claim