P = (A and (not B)) or (C and D)
Q = ((not A) or B) and (not (C or D))
R = P and Q
Jika A=False, B=True, C=True, D=False, maka nilai P, Q, dan R berturut-turut adalah?
A. OSN Easy - Medium
Quiz
•
Computers
•
11th Grade
•
Hard
Erwin Wijaya
Used 3+ times
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
P = (A and (not B)) or (C and D)
Q = ((not A) or B) and (not (C or D))
R = P and Q
Jika A=False, B=True, C=True, D=False, maka nilai P, Q, dan R berturut-turut adalah?
True, False, False
False, False, False
True, True, True
True, False, True
False, True, False
Answer explanation
P = (F and F) or (T and F) = F or F = F
Q = (T or T) and not (T or F) = T and F = F
R = F and F = F
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
100 burung memilih antara Alfa (60), Beta (50), dan Charlie (40).
Yang memilih dua kandidat: Alfa-Beta (20), Alfa-Charlie (15), Beta-Charlie (10).
Yang memilih ketiganya: 5 burung.
Tiap suara dibagi rata. Siapa yang dapat suara terbanyak?
Alfa
Beta
Charlie
Beta dan Charlie sama
Alfa dan Beta sama
Answer explanation
Hasil:
Alfa: 60×3 + 20×1.5 + 15×1.5 + 5×1 = 247.5
Beta: 50×3 + 20×1.5 + 10×1.5 + 5×1 = 217.5
Charlie: 40×3 + 15×1.5 + 10×1.5 + 5×1 = 197.5
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Berapakah digit terakhir dari 3^{2023}?
1
3
7
9
4
Answer explanation
Pola digit terakhir dari 3^n adalah: 3, 9, 7, 1 (ulang setiap 4).
2023 mod 4 = 3 → digit terakhir = 7.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Diberikan 5 kota dengan bobot antar kota:
A-B: 3
A-C: 4
B-C: 2
B-D: 6
C-E: 5
Berapa total MST (Minimum Spanning Tree)?
14
13
12
11
10
Answer explanation
Gunakan Kruskal:
Ambil edge terpendek tanpa membentuk siklus:
B-C (2), A-B (3), A-C (4) → skip (siklus), C-E (5), B-D (6)
→ Total = 2 + 3 + 5 + 2 = 12
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Jika 1+3+5+...+a=400, berapakah nilai a?
39
41
43
45
47
Answer explanation
Jumlah n bilangan ganjil pertama = n²
Cari n: n² = 400 → n = 20
a = bilangan ganjil ke-20 → a = 2×20 - 1 = 39
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Dari 12 bebek, Kwak harus dipilih, Kwik tidak boleh, pilih 6 bebek.
Berapa banyak cara?
210
252
462
330
165
Answer explanation
Total bebek = 12
Kwak harus dipilih → berarti sudah pasti 1 bebek dipilih, tinggal pilih 5 bebek lagi.
Kwik tidak boleh dipilih → jadi dari 12 bebek, kurangi 1 (Kwik) → tersisa 11 bebek, termasuk Kwak yang sudah dipilih.
Karena Kwak sudah dipilih, maka kita hanya boleh memilih 5 bebek dari:
11 bebek tanpa Kwik, dan juga tanpa Kwak (karena Kwak sudah dipilih).
Jadi, yang bisa dipilih = 11 - 1 = 10 bebek.
Maka =
(10/5)=10!/5!⋅5!=252
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Jika A = 13 (1101) dan B = 9 (1001), maka hasil dari A XOR B adalah?
4
5
8
12
0
Answer explanation
1101 XOR 1001 = 0100 = 4
A = 13 → dalam biner: 1101
B = 9 → dalam biner: 1001
1 XOR 1 = 0
1 XOR 0 = 1
0 XOR 0 = 0
1 XOR 1 = 0
---------
0100 (hasil XOR)
Ubah hasil ke desimal:
0100 (biner) = 4 (desimal)
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