What is tractive effort in electric traction?
Electric Traction Quiz

Quiz
•
Engineering
•
University
•
Medium
Gouthami Reddy
Used 1+ times
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The energy consumed per km
The force exerted by the train on the track
The force exerted by the motor on the wheels to move the train
The braking force applied during retardation
Answer explanation
Tractive effort refers to the force exerted by the motor on the wheels to move the train. This force is crucial for overcoming resistance and enabling acceleration, making it the correct choice among the options provided.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The tractive effort (F) required to accelerate a train is directly proportional to:
Train weight
Final speed
Acceleration
Both A and C
Answer explanation
The tractive effort (F) is directly proportional to both the train weight (A) and the acceleration (C). Therefore, the correct answer is 'Both A and C', as both factors influence the force needed to accelerate the train.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which factor does NOT affect specific energy consumption?
Train load
Track gradient
Number of passengers
Type of train windows
Answer explanation
The type of train windows does not influence specific energy consumption. In contrast, train load, track gradient, and number of passengers directly impact energy usage during operation.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the unit of specific energy consumption?
Newton
Joule
kWh/ton-km
Watt/km
Answer explanation
Specific energy consumption measures energy used per unit of transport, typically expressed as kWh/ton-km. This indicates how much energy is consumed to transport one ton of goods over one kilometer.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If a train of mass 300 tons accelerates at 0.5 m/s², what is the tractive effort?
1500 N
15000 N
150000 N
1.5 MN
Answer explanation
To find the tractive effort, use the formula: Force = mass × acceleration. Convert 300 tons to kg (300,000 kg) and calculate: 300,000 kg × 0.5 m/s² = 150,000 N or 1.5 MN. Thus, the correct answer is 1.5 MN.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The coefficient of adhesion is defined as:
Ratio of tractive effort to total weight
Ratio of adhesive weight to tractive effort
Ratio of tractive effort to adhesive weight
Ratio of adhesive weight to total train weight
Answer explanation
The coefficient of adhesion is defined as the ratio of tractive effort to adhesive weight. This measures how effectively a vehicle can utilize its weight to generate traction, making the correct choice: Ratio of tractive effort to adhesive weight.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If the adhesive weight is 50 tons and the coefficient of adhesion is 0.2, what is the maximum tractive effort without slipping?
10,000 N
100,000 N
50,000 N
200,000 N
Answer explanation
The maximum tractive effort can be calculated using the formula: Tractive Effort = Adhesive Weight × Coefficient of Adhesion. Here, 50 tons (50,000 kg) × 0.2 = 10,000 kgf, which converts to 100,000 N. Thus, the correct answer is 100,000 N.
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