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  5. Precalculus B: Conic Sections Hyperbola Test 2.0

Precalculus B: Conic Sections Hyperbola Test 2.0

Authored by Jeff Da Moude

Mathematics

9th - 12th Grade

CCSS covered

Precalculus B: Conic Sections Hyperbola Test 2.0
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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Write in standard hyperbolic form, x2−4y2+10x+32y−75=0x^2-4y^2+10x+32y-75=0 :

(x+5)2164−(y−4)241=1\frac{\left(x+5\right)^2}{164}-\frac{\left(y-4\right)^2}{41}=1

(x+5)236−(y+4)29=1\frac{\left(x+5\right)^2}{36}-\frac{\left(y+4\right)^2}{9}=1

(y−4)29−(x−5)236=1\frac{(y-4)^2}{9}-\frac{(x-5)^2}{36}=1

(x+5)236−(y−4)29=1\frac{(x+5)^2}{36}-\frac{(y-4)^2}{9}=1

Tags

CCSS.HSG.GPE.A.3

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What is the value of a² for the given hyperbola?

1

5

25

16

Tags

CCSS.HSG.GPE.A.3

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What are the equations of the asymptotes of the hyperbola in the picture?

y = x and y = -x

y = 2x and y = -2x

y = 1/2x and y = -1/2x

y = 2x and y = 4x

Tags

CCSS.HSG.GPE.A.3

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find the equation of the hyperbola.

(x−2)216−(y+3)220=1\frac{(x-2)^2}{16}-\frac{(y+3)^2}{20}=1

(x+3)216−(y−2)20=1\frac{(x+3)^2}{16}-\frac{(y-2)}{20}=1

(x−2)220−(y+3)216=1\frac{(x-2)^2}{20}-\frac{(y+3)^2}{16}=1

(y+3)216−(x−2)220=1\frac{(y+3)^2}{16}-\frac{(x-2)^2}{20}=1

Tags

CCSS.HSG.GPE.A.3

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is the center of the hyperbola?

y29−(x+4)2=1\frac{y^2}{9}-(x+4)^2=1

(0, 4)

(4, 0)

(-4, 0)

(0, -4)

6.

MATCH QUESTION

1 min • 1 pt

y2−x24=1y^2-\frac{x^2}{4}=1

vertices

(0,±1)\left(0,\pm1\right)

co-vertices

(±2,0)\left(\pm2,0\right)

center

(0,0)

foci

(0, ±5)\left(0,\ \pm\sqrt[]{5}\right)

7.

DRAG AND DROP QUESTION

1 min • 4 pts

(x−1)24−(y+2)21=1\frac{\left(x-1\right)^2}{4}-\frac{\left(y+2\right)^2}{1}=1

a=​ (a)  

b=​ (b)  

c=​ (c)  

in hyperbolas, true or false: c2=a2−b2c^2=a^2-b^2 ​ (d)  

false
true
2
1
√5
√3

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