DRILL May 6 Solving Quadratics

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2

Tags

CCSS.HSA-REI.B.4B

Solve

x² + 2x - 24 = 0

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring

x²+12x+35=0

• x = -5 or x = -7

• x = 5 or x = 7

• x = -35 or x = -1

• x = -9 or x = -4

Tags

CCSS.HSA-REI.B.4B

The solutions of the quadratic equation 
x²+2x-15=0 are

• x = 3 or x = 5
• x = 5 or x = -3
• x = -5 or x = 3
• x = -3 or x = -5

Tags

CCSS.HSA-REI.B.4B

Given the factors, what is the quadratic equation?
x + 7 and x + 10

Tags

CCSS.HSA-REI.B.4B

Give the factors, find the quadratic equation.
x + 5 and x - 8

Tags

CCSS.HSA-REI.B.4B

Given the roots, find the quadratic equation.

x = 5 and x = 3

Given the roots, find the quadratic equation.

x = 1 and x = -7