
Topic 21 Lessons 1-2 QUIZ
Authored by Joseph Ricci
Mathematics
10th Grade
CCSS covered
Used 7+ times

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20 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If 30% of the rectangle is shaded, what is the area of the unshaded region? (Rectangle dimensions: 8m by 4m)
22.4 square meters
19.2 square meters
9.6 square meters
12.8 square meters
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the area of the total UNSHADED region in the isosceles trapezoid with base lengths and height given in the diagram.
36 square centimeters
24 square centimeters
48 square centimeters
30 square centimeters
Tags
CCSS.6.G.A.1
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the circumference of a circle with a radius of 3 inches. (Use the formula C = 2πr)
The circumference is 6π inches (or approximately 18.85 inches).
The circumference is 9π inches (or approximately 28.27 inches).
The circumference is 3π inches (or approximately 9.42 inches).
The circumference is 12π inches (or approximately 37.70 inches).
Tags
CCSS.7.G.B.4
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Consider a circle that has rolled from the origin to point G so that OG is the circumference of the circle. Use the diagram to make a statement about the ratio of the circumference to the radius. In other words, what is special about the ratio of the distance the circle rolled to the height of the circle?
The ratio is always 2.
The ratio is always π.
The ratio is always 1/2.
The ratio is always 4.
Tags
CCSS.7.G.B.4
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the circumference of the following circle: r = 5. (Use the formula C = 2πr)
C = 2π(5) = 10π
C = 2π(5) = 5π
C = 2π(5) = 25π
C = 2π(5) = 20π
Tags
CCSS.7.G.B.4
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the circumference of the following circle: d = 18. (Use the formula C = πd)
C = π(18) = 18π
C = π(18) = 9π
C = π(18) = 36π
C = π(18) = 81π
Tags
CCSS.7.G.B.4
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the circumference of the following circle: d = 3/4. (Use the formula C = πd)
C = π(3/4) = (3/4)π
C = π(3/4) = (4/3)π
C = π(3/4) = 3π
C = π(3/4) = (3/2)π
Tags
CCSS.7.G.B.4
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