08.1 - Sine, Cosine, and Tangent

Quiz
•
Mathematics
•
9th - 12th Grade
•
Hard
+4
Standards-aligned
Denise Lum
FREE Resource
22 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = ?, BC = 8, AC = 15.
sin A = 8/17
sin B = 15/17
cos A = 15/17
cos B = 8/17
tan A = 8/15
tan B = 15/8
sin A = 15/17
sin B = 8/17
cos A = 8/17
cos B = 15/17
tan A = 15/8
tan B = 8/15
sin A = 8/15
sin B = 15/8
cos A = 15/8
cos B = 8/15
tan A = 8/17
tan B = 15/17
sin A = 15/8
sin B = 8/15
cos A = 8/15
cos B = 15/8
tan A = 17/8
tan B = 17/15
Answer explanation
Using the Pythagorean theorem, the missing side AB is 17. For angle A, sin A = opposite/hypotenuse = 8/17, cos A = adjacent/hypotenuse = 15/17, tan A = opposite/adjacent = 8/15. For angle B, sin B = 15/17, cos B = 8/17, tan B = 15/8.
Tags
CCSS.HSG.SRT.C.6
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = ?, BC = ?, AC = 24, BC = 7.
sin A = 7/25
sin B = 24/25
cos A = 24/25
cos B = 7/25
tan A = 7/24
tan B = 24/7
sin A = 24/25
sin B = 7/25
cos A = 7/25
cos B = 24/25
tan A = 24/7
tan B = 7/24
sin A = 24/25
sin B = 7/25
cos A = 24/25
cos B = 7/25
tan A = 7/24
tan B = 24/7
sin A = 7/24
sin B = 24/25
cos A = 24/25
cos B = 7/25
tan A = 7/25
tan B = 24/7
Answer explanation
Using the Pythagorean theorem, the missing side AB is 25. For angle A, sin A = opposite/hypotenuse = 7/25, cos A = adjacent/hypotenuse = 24/25, and tan A = opposite/adjacent = 7/24. For angle B, sin B = 24/25, cos B = 7/25, tan B = 24/7.
Tags
CCSS.HSG.SRT.C.6
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = 15, BC = ?, AC = 12.
sin A = 3/5
sin B = 4/5
cos A = 4/5
cos B = 3/5
tan A = 3/4
tan B = 4/3
sin A = 4/5
sin B = 3/5
cos A = 3/5
cos B = 4/5
tan A = 4/3
tan B = 3/4
sin A = 12/15
sin B = 15/12
cos A = 15/12
cos B = 12/15
tan A = 12/9
tan B = 15/9
sin A = 15/12
sin B = 12/15
cos A = 12/15
cos B = 15/12
tan A = 9/12
tan B = 9/15
Answer explanation
Using the Pythagorean theorem, find BC = 9. For angle A, sin A = opposite/hypotenuse = 9/15 = 3/5, cos A = adjacent/hypotenuse = 12/15 = 4/5, tan A = opposite/adjacent = 9/12 = 3/4. For angle B, sin B = 12/15 = 4/5, cos B = 9/15 = 3/5, tan B = 12/9 = 4/3.
Tags
CCSS.HSG.SRT.C.6
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = ?, BC = 13, AC = 12.
sin A = 12/17
sin B = 13/17
cos A = 13/17
cos B = 12/17
tan A = 12/13
tan B = 13/12
sin A = 13/17
sin B = 12/17
cos A = 12/17
cos B = 13/17
tan A = 13/12
tan B = 12/13
sin A = 5/13
sin B = 12/13
cos A = 12/13
cos B = 5/13
tan A = 5/12
tan B = 12/5
sin A = 12/13
sin B = 5/13
cos A = 5/13
cos B = 12/13
tan A = 12/5
tan B = 5/12
Answer explanation
Using the Pythagorean theorem, the missing side AB is 5. For angle A, sin A = opposite/hypotenuse = 12/13, cos A = adjacent/hypotenuse = 5/13, tan A = opposite/adjacent = 12/5. For angle B, sin B = 5/13, cos B = 12/13, tan B = 5/12.
Tags
CCSS.HSG.SRT.C.6
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Use right-triangle trigonometry to find the value for x, without calculator. Once you have solved for x without calculator, use a scientific calculator to find the value of x to the nearest thousandth (i.e. 3 decimal place accuracy). Triangle: Right triangle with sides AB = 18, angle BAC = 25°, AC = x.
5.432
10.256
16.314
12.789
Answer explanation
Using the sine function, sin(25°) = opposite/hypotenuse = AB/x. Thus, x = AB/sin(25°) = 18/sin(25°) ≈ 16.314. The correct answer is 16.314.
Tags
CCSS.HSG.SRT.C.8
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Use right-triangle trigonometry to find the value for x, without calculator. Once you have solved for x without calculator, use a scientific calculator to find the value of x to the nearest thousandth (i.e. 3 decimal place accuracy). Triangle: Right triangle with angle BAC = 20°, AC = x, BC = 8.
x = 8 / sin(20°) ≈ 23.399
x = 8 * sin(20°) ≈ 2.736
x = 8 / cos(20°) ≈ 8.514
x = 8 * cos(20°) ≈ 7.519
Answer explanation
In triangle ABC, angle BAC = 20° and side BC = 8. To find AC (x), use the sine function: sin(20°) = opposite/hypotenuse = 8/x. Rearranging gives x = 8/sin(20°). Thus, the correct choice is x = 8 / sin(20°) ≈ 23.399.
Tags
CCSS.HSG.SRT.C.8
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Use right-triangle trigonometry to find the value for x, without calculator. Once you have solved for x without calculator, use a scientific calculator to find the value of x to the nearest thousandth (i.e. 3 decimal place accuracy). Triangle: Right triangle with angle BAC = x°, AC = 8, BC = 13.
x = arccos(8/13) ≈ 50.317°
x = arcsin(8/13) ≈ 38.682°
x = arccos(13/8) ≈ 58.482°
x = arctan(8/13) ≈ 31.744°
Answer explanation
In triangle ABC, with AC = 8 and BC = 13, we use arctan to find angle x. Since tan(x) = opposite/adjacent = AC/BC = 8/13, we have x = arctan(8/13) ≈ 31.744°.
Tags
CCSS.HSG.SRT.C.8
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