08.1 - Sine, Cosine, and Tangent

08.1 - Sine, Cosine, and Tangent

9th - 12th Grade

22 Qs

quiz-placeholder

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08.1 - Sine, Cosine, and Tangent

08.1 - Sine, Cosine, and Tangent

Assessment

Quiz

Mathematics

9th - 12th Grade

Hard

CCSS
HSG.SRT.C.8, HSG.SRT.C.6, HSG.SRT.C.7

+4

Standards-aligned

Created by

Denise Lum

FREE Resource

22 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = ?, BC = 8, AC = 15.

sin A = 8/17

sin B = 15/17

cos A = 15/17

cos B = 8/17

tan A = 8/15

tan B = 15/8

sin A = 15/17

sin B = 8/17

cos A = 8/17

cos B = 15/17

tan A = 15/8

tan B = 8/15

sin A = 8/15

sin B = 15/8

cos A = 15/8

cos B = 8/15

tan A = 8/17

tan B = 15/17

sin A = 15/8

sin B = 8/15

cos A = 8/15

cos B = 15/8

tan A = 17/8

tan B = 17/15

Answer explanation

Using the Pythagorean theorem, the missing side AB is 17. For angle A, sin A = opposite/hypotenuse = 8/17, cos A = adjacent/hypotenuse = 15/17, tan A = opposite/adjacent = 8/15. For angle B, sin B = 15/17, cos B = 8/17, tan B = 15/8.

Tags

CCSS.HSG.SRT.C.6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = ?, BC = ?, AC = 24, BC = 7.

sin A = 7/25

sin B = 24/25

cos A = 24/25

cos B = 7/25

tan A = 7/24

tan B = 24/7

sin A = 24/25

sin B = 7/25

cos A = 7/25

cos B = 24/25

tan A = 24/7

tan B = 7/24

sin A = 24/25

sin B = 7/25

cos A = 24/25

cos B = 7/25

tan A = 7/24

tan B = 24/7

sin A = 7/24

sin B = 24/25

cos A = 24/25

cos B = 7/25

tan A = 7/25

tan B = 24/7

Answer explanation

Using the Pythagorean theorem, the missing side AB is 25. For angle A, sin A = opposite/hypotenuse = 7/25, cos A = adjacent/hypotenuse = 24/25, and tan A = opposite/adjacent = 7/24. For angle B, sin B = 24/25, cos B = 7/25, tan B = 24/7.

Tags

CCSS.HSG.SRT.C.6

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = 15, BC = ?, AC = 12.

sin A = 3/5

sin B = 4/5

cos A = 4/5

cos B = 3/5

tan A = 3/4

tan B = 4/3

sin A = 4/5

sin B = 3/5

cos A = 3/5

cos B = 4/5

tan A = 4/3

tan B = 3/4

sin A = 12/15

sin B = 15/12

cos A = 15/12

cos B = 12/15

tan A = 12/9

tan B = 15/9

sin A = 15/12

sin B = 12/15

cos A = 12/15

cos B = 15/12

tan A = 9/12

tan B = 9/15

Answer explanation

Using the Pythagorean theorem, find BC = 9. For angle A, sin A = opposite/hypotenuse = 9/15 = 3/5, cos A = adjacent/hypotenuse = 12/15 = 4/5, tan A = opposite/adjacent = 9/12 = 3/4. For angle B, sin B = 12/15 = 4/5, cos B = 9/15 = 3/5, tan B = 12/9 = 4/3.

Tags

CCSS.HSG.SRT.C.6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Find the sine, cosine, and tangent ratios for angle A and for angle B in the following triangle. (Hint: Use the Pythagorean theorem to find the missing side in the triangle first.) Triangle: Right triangle with sides AB = ?, BC = 13, AC = 12.

sin A = 12/17

sin B = 13/17

cos A = 13/17

cos B = 12/17

tan A = 12/13

tan B = 13/12

sin A = 13/17

sin B = 12/17

cos A = 12/17

cos B = 13/17

tan A = 13/12

tan B = 12/13

sin A = 5/13

sin B = 12/13

cos A = 12/13

cos B = 5/13

tan A = 5/12

tan B = 12/5

sin A = 12/13

sin B = 5/13

cos A = 5/13

cos B = 12/13

tan A = 12/5

tan B = 5/12

Answer explanation

Using the Pythagorean theorem, the missing side AB is 5. For angle A, sin A = opposite/hypotenuse = 12/13, cos A = adjacent/hypotenuse = 5/13, tan A = opposite/adjacent = 12/5. For angle B, sin B = 5/13, cos B = 12/13, tan B = 5/12.

Tags

CCSS.HSG.SRT.C.6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Use right-triangle trigonometry to find the value for x, without calculator. Once you have solved for x without calculator, use a scientific calculator to find the value of x to the nearest thousandth (i.e. 3 decimal place accuracy). Triangle: Right triangle with sides AB = 18, angle BAC = 25°, AC = x.

5.432

10.256

16.314

12.789

Answer explanation

Using the sine function, sin(25°) = opposite/hypotenuse = AB/x. Thus, x = AB/sin(25°) = 18/sin(25°) ≈ 16.314. The correct answer is 16.314.

Tags

CCSS.HSG.SRT.C.8

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Use right-triangle trigonometry to find the value for x, without calculator. Once you have solved for x without calculator, use a scientific calculator to find the value of x to the nearest thousandth (i.e. 3 decimal place accuracy). Triangle: Right triangle with angle BAC = 20°, AC = x, BC = 8.

x = 8 / sin(20°) ≈ 23.399

x = 8 * sin(20°) ≈ 2.736

x = 8 / cos(20°) ≈ 8.514

x = 8 * cos(20°) ≈ 7.519

Answer explanation

In triangle ABC, angle BAC = 20° and side BC = 8. To find AC (x), use the sine function: sin(20°) = opposite/hypotenuse = 8/x. Rearranging gives x = 8/sin(20°). Thus, the correct choice is x = 8 / sin(20°) ≈ 23.399.

Tags

CCSS.HSG.SRT.C.8

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Use right-triangle trigonometry to find the value for x, without calculator. Once you have solved for x without calculator, use a scientific calculator to find the value of x to the nearest thousandth (i.e. 3 decimal place accuracy). Triangle: Right triangle with angle BAC = x°, AC = 8, BC = 13.

x = arccos(8/13) ≈ 50.317°

x = arcsin(8/13) ≈ 38.682°

x = arccos(13/8) ≈ 58.482°

x = arctan(8/13) ≈ 31.744°

Answer explanation

In triangle ABC, with AC = 8 and BC = 13, we use arctan to find angle x. Since tan(x) = opposite/adjacent = AC/BC = 8/13, we have x = arctan(8/13) ≈ 31.744°.

Tags

CCSS.HSG.SRT.C.8

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