Solving Equations and Inequalities

Authored by ULISSES MONTES

Mathematics

9th - 12th Grade

CCSS covered

Used 2+ times

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20 questions

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DRAG AND DROP QUESTION

30 sec • 5 pts

The first step when solving $-11=\frac{5z-3}{-2}$ is to (a) .

Multiply by -2

Divide by 5

Add 3

Add 11

Tags

CCSS.7.EE.B.4A

DROPDOWN QUESTION

15 mins • 1 pt

The value of x that satisfies the equation 4(2x - 3) = 6x + 2 is (a) .

x = 5/2

x = 7

x = 1

no solution

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

MULTIPLE SELECT QUESTION

30 sec • 5 pts

Solve. Select BOTH solutions.

$\left|x-1\right|=3$

-2

-3

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

Solve for x in the following absolute value equation.
$\left|\ \frac{x}{4}\right|\ =\ 8$

$\left\{\ 2,\ -2\ \right\}$

$\left\{\ \frac{1}{2}\ ,\ -\frac{1}{2}\right\}$

$\left\{\ 12,\ -12\ \right\}$

$\left\{\ 32,\ -32\ \right\}$

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

2 mins • 5 pts

What's a way to define absolute value?

The value of a number

The opposite of a number

The distance of a number from zero

The multiplicative inverse of a number

Tags

CCSS.6.NS.C.7C

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$Given\ ax-b=c,\ solve\ for\ x.\$

$x\ =\ \frac{c+b}{a}$

$x\ =\ \frac{c-b}{a}$

$x\ =\ \frac{a+b}{c}$

$x\ =\ \frac{c+a}{b}$

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

2x + 3(5x - 7) = 47

Tags

CCSS.8.EE.C.7B

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Solve the equation:
-5(x + 3) = 2(x - 5)

x = $\frac{13}{7}$

x = $-\frac{5}{7}$

x = $-\frac{25}{7}$

x = $\frac{7}{5}$

x = $-\frac{13}{3}$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve the equation involving absolute value: $|x - 3| = 5$ .

$x = 8$ or $x = -2$

$x = 8$ or $x = 2$

$x = -8$ or $x = 2$

$x = 8$ or $x = 3$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve the multi-step inequality: $2x + 5 > 3x - 4$ .

$x < 9$

$x > 9$

$x < -9$

$x > -9$

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Solving Equations and Inequalities

The first step when solving −11=5z−3−2-11=\frac{5z-3}{-2}−11=−25z−3​ is to (a) .

The value of x that satisfies the equation 4(2x - 3) = 6x + 2 is (a) .

Solve. Select BOTH solutions. ∣x−1∣=3\left|x-1\right|=3∣x−1∣=3

Solve for x in the following absolute value equation. ∣ x4∣ = 8\left|\ \frac{x}{4}\right|\ =\ 8​ 4x​​ = 8

What's a way to define absolute value?

Given ax−b=c, solve for x. Given\ ax-b=c,\ solve\ for\ x.\ Given ax−b=c, solve for x.

2x + 3(5x - 7) = 47

Solve the equation:-5(x + 3) = 2(x - 5)

Solve the equation involving absolute value: ∣x−3∣=5|x - 3| = 5∣x−3∣=5 .

Solve the multi-step inequality: 2x+5>3x−42x + 5 > 3x - 42x+5>3x−4 .

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Discover more resources for Mathematics

The first step when solving $-11=\frac{5z-3}{-2}$ is to (a) .

Solve. Select BOTH solutions.

$\left|x-1\right|=3$

Solve for x in the following absolute value equation.
$\left|\ \frac{x}{4}\right|\ =\ 8$

$Given\ ax-b=c,\ solve\ for\ x.\$

Solve the equation:
-5(x + 3) = 2(x - 5)

Solve the equation involving absolute value: $|x - 3| = 5$ .

Solve the multi-step inequality: $2x + 5 > 3x - 4$ .