Specific Heat

The specific heat of platinum is 0.133 J/g°C. How much heat(Q) is released when a 10 g piece of platinum cools from 100°C to 50°C?

• 66.5 J

• 665 J

• 0.0266 J

• 0.665 J

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

20 g of water. specific heat of water is 4.18 J/g°C. temperature changes from 25° C to 20° C, how much heat energy (Q) moves from the water to the surroundings?

• 418 J

• 209 J

• 83 J

• 4.18 J

Tags

NGSS.MS-PS1-4

The SI units J/g°C measures

• Specific heat

• mass

• temperature

• heat energy

Tags

NGSS.MS-PS3-4

The specific heat(c) of copper is 0.39 J/g °C. What is the temperature change(∆t) when 100 Joules of heat(Q) is added to 20 grams?

• 12.82 °C

• 24.12°C

• 1.95 °C

• 5128 °C

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

Copper, Stainless Steel, Carbon Steel, and Zinc were all heated using the same thermal energy.  What material would be the coolest after being heated?

• Copper
• Carbon Steel
• Zinc
• Stainless Steel

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

_______________ describes how much energy is required to raise an object's temperature.

• Conduction
• Convection
• Specific Heat
• Radiation

A pot of 2400g of water at a temperature of 25˚C is heated on a stove until the water boils (100˚C).  The specific heat of water is 4.18 J/(g˚C).
Determine the heat energy needed to heat the water in the pot to boiling.

• 133.76J
• 43,062.2J
• 752,400J
• 1,003,200J

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

Specific heat of water is  4.18 J/g°C. Specific heat of wood is 1.760 J/g°C What material needs more heat energy to raise the temperature?

• Water
• Wood
• Both are same

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

The temperature of an unknown piece of metal with a mass of 30.00 g changes from 25.0 °C to 35.0 °C when the metal absorbs 350.0 J of energy. What is the specific heat of the metal?

• 1.17 J/g°C
• -1.17 J/g°C
• 0.857 J/g°C
• -0.857 J/g°C

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

What  is the formula to calculate heat energy required to raise the temperature of any substance?

• Q=mc∆t
• Q=mc
• Q= ½mv
• m=QC

Tags

NGSS.MS-PS3-3

NGSS.MS-PS3-4