Solving Literal Equations and Formulas

Solving Literal Equations and Formulas

Assessment

Interactive Video

Mathematics

6th - 10th Grade

Medium

CCSS
HSA.CED.A.4, HSA.REI.B.3, 6.EE.A.2C

+1

Standards-aligned

Created by

Mia Campbell

Used 3+ times

FREE Resource

Standards-aligned

CCSS.HSA.CED.A.4
,
CCSS.HSA.REI.B.3
,
CCSS.6.EE.A.2C
CCSS.6.EE.C.9
,
The video tutorial covers solving literal equations, which involve equations with multiple variables. It provides examples of isolating specific variables in various formulas, such as perimeter, simple interest, and volume. Techniques like using properties of equality and handling fractions are demonstrated to solve for variables like side length, principal, width, and height.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a literal equation?

An equation with only constants

An equation with no variables

An equation with more than one variable

An equation with only one variable

Tags

CCSS.HSA.CED.A.4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation P = 4s, what is the value of s when P = 20?

5

8

4

6

Tags

CCSS.6.EE.A.2C

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the simple interest formula I = PRT, how do you solve for P?

P = I - RT

P = I * RT

P = I / (RT)

P = I + RT

Tags

CCSS.HSA.CED.A.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the formula P = 2L + 2W, how do you isolate W?

W = 2L - P

W = P + 2L

W = P / 2L

W = (P - 2L) / 2

Tags

CCSS.HSA.CED.A.4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for y in the equation X + 5Y = 15?

Y = (15 - X) / 5

Y = 15 - X

Y = 5 / (15 - X)

Y = X / 15

Tags

CCSS.6.EE.C.9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation X = (A + B) / 2, what is the first step to solve for B?

Add A to both sides

Divide both sides by 2

Subtract A from both sides

Multiply both sides by 2

Tags

CCSS.HSA.REI.B.3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for M in the equation D = (C - M) / 2?

M = 2D + C

M = 2D - C

M = C - 2D

M = D / 2 - C

Tags

CCSS.HSA.CED.A.4

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