
Finding Vertex Form of Quadratic Functions

Interactive Video
•
Mathematics
•
8th - 12th Grade
•
Hard
Standards-aligned

Liam Anderson
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the coordinates of the vertex of the quadratic function?
(0, 0)
(2, -4)
(-2, -4)
(1, 9)
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Through which point does the quadratic function pass?
(2, -4)
(0, 0)
(-2, -4)
(1, 9)
Tags
CCSS.HSF-IF.C.7A
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the vertex form of a quadratic function?
y = a(x + h)^2 + k
y = ax^2 + bx + c
y = a(x - h)^2 + k
y = mx + b
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What values are substituted for h and k in the vertex form equation?
h = 1, k = 9
h = -1, k = -9
h = -2, k = -4
h = 2, k = 4
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the simplified form of the equation after substituting the vertex?
y = a(x + 2)^2 + 4
y = a(x - 2)^2 + 4
y = a(x + 2)^2 - 4
y = a(x - 2)^2 - 4
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step after substituting the vertex into the equation?
Find the y-intercept.
Solve for x.
Graph the function.
Find the value of 'a' by substituting the given point.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What equation do we get after substituting the point (1, 9) into the simplified equation?
9 = a(1 + 2)^2 - 4
9 = a(1 - 2)^2 + 4
9 = a(1 - 2)^2 - 4
9 = a(1 + 2)^2 + 4
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