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Solving Equations with Variables on Both Sides

Solving Equations with Variables on Both Sides

Assessment

Interactive Video

Mathematics

6th - 10th Grade

Practice Problem

Hard

CCSS
6.EE.A.3, HSA-REI.B.4B, 7.EE.A.1

+1

Standards-aligned

Created by

Aiden Montgomery

FREE Resource

Standards-aligned

CCSS.6.EE.A.3
,
CCSS.HSA-REI.B.4B
,
CCSS.7.EE.A.1
CCSS.6.EE.B.7
,
Mr. Champlin guides students through solving equations with variables on both sides, focusing on distribution and combining like terms. He also covers solving equations with fractions by finding the least common denominator. The tutorial includes step-by-step instructions and encourages students to verify their solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of this tutorial?

Solving equations with variables on both sides

Solving quadratic equations

Factoring polynomials

Graphing linear equations

Tags

CCSS.HSA-REI.B.4B

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation 6 - 3(x + 5) = 3x - x - 11?

Subtract 5 from both sides

Add 3 to both sides

Distribute the negative 3

Combine like terms

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After distributing, what is the simplified form of 6 - 3(x + 5)?

6 + 3x + 15

6 - 3x - 15

6 - 3x + 15

6 + 3x - 15

Tags

CCSS.6.EE.A.3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What do you get when you combine like terms on the left side of the equation 6 - 3x - 15?

9 + 3x

-9 + 3x

9 - 3x

-9 - 3x

Tags

CCSS.7.EE.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after combining like terms in the equation -9 - 3x = 2x + 11?

Divide by 5

Multiply by 2

Subtract 11 from both sides

Add 3x to both sides

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the least common denominator for the fractions 1, 4, and 3?

6

16

8

12

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What do you get when you multiply the entire equation by the least common denominator?

12x = 3x - 1 - 4

12x = 3x + 4 - 1

12x = 3x + 1 - 4

12x = 3x + 1 + 4

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