Solving Systems by Graphing: Part 2 Challenge

Solving Systems by Graphing: Part 2 Challenge

Assessment

Interactive Video

Mathematics

6th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial covers solving systems of equations by graphing, focusing on identifying the point of intersection of two lines. It explains scenarios where systems have no solution, such as parallel lines, and when they have infinitely many solutions, like overlapping lines. The tutorial also discusses the types of solutions: one solution, no solution, and infinitely many solutions. Examples are provided to illustrate graphing techniques and solution determination.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are we looking for when solving a system of equations by graphing?

The point where the two lines intersect

The point where the two lines are tangent

The point where the two lines are perpendicular

The point where the two lines are parallel

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of lines never cross and have no solution?

Tangent lines

Perpendicular lines

Intersecting lines

Parallel lines

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be true for two lines to have infinitely many solutions?

They must be parallel

They must overlap at every point

They must intersect at one point

They must be perpendicular

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the condition for two lines to intersect at exactly one point?

They have the same slope and different y-intercepts

They have different slopes

They have the same slope and same y-intercept

They are perpendicular

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the slope of the line represented by the equation y = 2x - 3?

2

-3

1

0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you rewrite the equation 2y = 4x + 2 in slope-intercept form?

y = 4x + 2

y = 2x - 1

y = x + 2

y = 2x + 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-intercept of the line represented by the equation y = -1/2x + 4?

-1/2

4

2

0

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