Solving Multi-Step Linear Equations

What is the initial equation given in the problem?

• 20 - 6y = 7y - 6

• 20 + 6y = 7y + 6

• 20 + 7y = 6y + 6

• 20 - 7y = 6y - 6

Tags

CCSS.7.EE.B.4A

What operation is performed to eliminate -7y from the left-hand side?

• Subtract 7y from both sides

• Multiply both sides by 7y

• Add 7y to both sides

• Divide both sides by 7y

After adding 7y to both sides, what is the resulting equation?

• 20 = 6y + 7y - 6

• 20 = 13y + 6

• 20 = 6y - 7y + 6

• 20 = 13y - 6

Tags

CCSS.HSA.REI.A.1

What is the next step after obtaining 26 = 13y?

• Multiply both sides by 13

• Subtract 13 from both sides

• Divide both sides by 13

• Add 13 to both sides

Tags

CCSS.6.EE.B.7

What is the value of y after solving 26 = 13y?

• y = 4

• y = 3

• y = 2

• y = 1

Tags

CCSS.7.EE.B.4A

Why might it be simpler to isolate y on the right-hand side?

• It results in a smaller equation

• It eliminates the need for subtraction

• It results in a positive coefficient for y

• It avoids fractions

What is the equation after subtracting 6y from both sides?

• 20 - 13y = -6

• 20 + 13y = -6

• 20 + 7y = 6y + 6

• 20 - 7y = 6y - 6

Tags

CCSS.6.EE.B.7

What is the result of dividing both sides of -13y = -26 by -13?

• y = -2

• y = 1

• y = 2

• y = -1

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the purpose of substituting y = 2 back into the original equation?

• To eliminate y

• To simplify the equation

• To verify the solution

• To find a new solution

What is the final verification result when y = 2 is substituted back?

• 6 = 8

• 6 = 4

• 6 = 6

• 6 = 2