Exploring Literal Equations and Their Foundations

What should you do if you don't have the yellow packet?

• Wait until you get the packet

• Ask a friend for their packet

• Get paper and write down each problem

• Skip the assignment

Tags

CCSS.HSA.CED.A.4

How do you isolate x in the equation z = x + m?

• Divide both sides by m

• Multiply both sides by m

• Subtract m from both sides

• Add m to both sides

Tags

CCSS.6.EE.B.7

In the equation c + x = g, what is the first step to isolate x?

• Multiply both sides by c

• Subtract c from both sides

• Add c to both sides

• Divide both sides by c

Tags

CCSS.HSA.REI.B.3

What is the result of solving for x in the equation k - x = u?

• x = u + k

• x = u - k

• x = -u + k

• x = k - u

Tags

CCSS.HSA.CED.A.4

How do you solve for a in the equation u/a = k?

• Multiply both sides by a

• Divide both sides by u

• Multiply both sides by u

• Divide both sides by a

Tags

CCSS.HSA.REI.A.1

What is the first step to solve for x in the equation -4x - 4 = u?

• Multiply both sides by -4

• Subtract 4 from both sides

• Divide both sides by -4

• Add 4 to both sides

Tags

CCSS.HSA.REI.A.1

In the equation 2x - 4 = g, what is the next step after adding 4 to both sides?

• Add 2 to both sides

• Subtract 2 from both sides

• Divide both sides by 2

• Multiply both sides by 2

Tags

CCSS.HSA.CED.A.4

How do you solve for y in the equation 3y + 4x = -12?

• Add 4x to both sides, then divide by 3

• Subtract 4x from both sides, then divide by 3

• Divide both sides by 3, then subtract 4x

• Multiply both sides by 3, then subtract 4x

Tags

CCSS.6.EE.C.9

What is the result of solving for y in the equation -y = -2x - 6?

• y = -2x - 6

• y = 2x - 6

• y = -2x + 6

• y = 2x + 6

Tags

CCSS.HSA.REI.B.3

How do you solve for y in the equation -4y = 4x - 3?

• Multiply both sides by -4

• Subtract 4 from both sides

• Add 4 to both sides

• Divide both sides by -4

Tags

CCSS.HSA.REI.B.3