Solving Rational Equations in Algebra II

What are the constraints given for the variable x in the equation?

• x cannot be 0 or 1

• x cannot be -3 or 1

• x cannot be -1 or 3

• x cannot be -3 or 3

Tags

CCSS.HSA.REI.A.2

Why can't x be -3 or 1 in the given equation?

• Because it would make the equation positive

• Because it would make the equation equal to zero

• Because it would make the equation undefined

• Because it would make the equation negative

Tags

CCSS.HSA.REI.A.2

What is the first step to eliminate the denominators in the equation?

• Add x to both sides

• Subtract x from both sides

• Divide both sides by x minus 1

• Multiply both sides by x plus 3

Tags

CCSS.HSA.REI.A.2

What do you achieve by multiplying both sides of the equation by x minus 1?

• It divides the equation by x minus 1

• It subtracts x minus 1 from the numerator

• It adds x minus 1 to the numerator

• It cancels out the x minus 1 in the denominator

Tags

CCSS.HSA.REI.A.2

What is the result of cross-multiplying the equation 5/(x-1) = 3/(x+3)?

• 5(x + 3) = 3(x - 1)

• 5x + 3 = 3x - 1

• 5x - 1 = 3x + 3

• 5(x - 1) = 3(x + 3)

Tags

CCSS.HSA.REI.A.2

What is the simplified form of 5(x + 3)?

• 5x + 3

• 5x + 15

• 5x - 3

• 5x - 15

Tags

CCSS.6.EE.A.3

After distributing and simplifying, what is the equation before isolating x?

• 5x + 15 = 3x - 3

• 5x - 15 = 3x + 3

• 5x + 3 = 3x - 1

• 5x - 3 = 3x + 1

What is the value of x after solving the equation 2x + 15 = -3?

• x = 9

• x = 6

• x = -6

• x = -9

Tags

CCSS.7.EE.B.4A

What is the left-hand side of the equation when x = -9?

• 5/(-9 + 3)

• 5/(-9 + 1)

• 5/(-9 - 1)

• 5/(-9 - 3)

Tags

CCSS.6.EE.A.2C

What is the right-hand side of the equation when x = -9?

• 3/(-9 + 3)

• 3/(-9 - 3)

• 3/(-9 + 1)

• 3/(-9 - 1)

Tags

CCSS.6.EE.A.2C