Identifying Solutions to Two-Step Linear Equations

The video tutorial guides viewers through solving a linear equation in one variable by testing potential solutions. The equation given is -2(V + 8) = -26, and the potential values for V are 5, -10, 8, and -2. The instructor demonstrates how to substitute each value into the equation, simplify using order of operations, and determine if the left-hand side equals the right-hand side. The only correct solution is V = 5, as it satisfies the equation, while the other values do not.

What is the given equation in the video?

• 2(V + 8) = 26

• -2(V + 8) = -26

• -2(V - 8) = -26

• 2(V - 8) = 26

Tags

CCSS.7.EE.B.4A

What is the first potential solution tested for V?

• -2

• 8

• 5

• -10

Tags

CCSS.HSA-REI.B.4B

What is the result when V = 5 is substituted into the equation?

• Cannot be determined

• Undefined

• False

• True

Tags

CCSS.6.EE.B.5

What is the second potential solution tested for V?

• 8

• 5

• -10

• -2

Tags

CCSS.HSA-REI.B.4B

What is the result when V = -10 is substituted into the equation?

• Undefined

• False

• Cannot be determined

• True

Tags

CCSS.6.EE.B.5

What is the third potential solution tested for V?

• 8

• -2

• 5

• -10

Tags

CCSS.HSA-REI.B.4B

What is the result when V = 8 is substituted into the equation?

• Cannot be determined

• Undefined

• False

• True

Tags

CCSS.6.EE.B.5

What is the fourth potential solution tested for V?

• 5

• -2

• -10

• 8

Tags

CCSS.HSA-REI.B.4B

What is the result when V = -2 is substituted into the equation?

• Cannot be determined

• Undefined

• False

• True

Tags

CCSS.6.EE.B.5

Which value was found to be the correct solution for the equation?

• -10

• 5

• -2

• 8

Tags

CCSS.7.EE.B.4A