Solving Algebraic Word Problems with Money

This video tutorial is part of an algebra lesson focusing on solving word problems involving money. The problem involves a bank teller with a total of 180 bills, consisting of $20 and $10 bills, with a total cash value of $3,050. The tutorial guides students through defining variables, setting up equations, and solving them to find the number of each type of bill. The solution involves basic algebraic manipulation, including distributing, combining like terms, and solving for variables.

What is the total number of bills in the drawer?

• 150

• 180

• 200

• 220

If x represents the number of $20 bills, how do we express the number of $10 bills?

• x - 180

• x + 180

• 180 - x

• 180 + x

What is the total cash value of the bills in the drawer?

• $3,100

• $3,000

• $3,050

• $3,200

How do you calculate the value of the $20 bills?

• x / 20

• 20 * x

• x - 20

• 20 + x

What is the equation formed to represent the total value of the bills?

• 20x + 10x = 3,050

• 20x - 10(180 - x) = 3,050

• 20 + 10(180 - x) = 3,050

• 20x + 10(180 - x) = 3,050

What is the first step in solving the equation?

• Divide both sides by 10

• Subtract 10x from 20x

• Distribute 10 to both terms inside the parentheses

• Add 20x and 10x

After distributing, what is the simplified form of the equation?

• 20x - 10x = 3,050

• 20x + 1800 - 10x = 3,050

• 20x - 1800 + 10x = 3,050

• 20x + 10x = 3,050

What is the value of x after solving the equation?

• 150

• 125

• 100

• 175

How many $20 bills are in the drawer?

• 150

• 125

• 180

• 55

How many $10 bills are in the drawer?

• 55

• 180

• 150

• 125