Solve One-Step Equations Challenge

Solve One-Step Equations Challenge

Assessment

Interactive Video

Mathematics

6th - 10th Grade

Practice Problem

Hard

CCSS
6.EE.B.7, 7.EE.B.4A, 3.OA.C.7

Standards-aligned

Created by

Liam Anderson

FREE Resource

Standards-aligned

CCSS.6.EE.B.7
,
CCSS.7.EE.B.4A
,
CCSS.3.OA.C.7

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does 'inverse operation' mean in the context of solving equations?

Performing the same operation on both sides of the equation

Using a complex operation to simplify the equation

Applying the opposite operation to isolate the variable

Ignoring the operation to focus on the variable

Tags

CCSS.6.EE.B.7

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the goal when isolating a variable in an equation?

To multiply the variable

To eliminate the variable

To get the variable by itself on one side of the equation

To combine like terms

Tags

CCSS.7.EE.B.4A

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean to 'isolate' the variable in an equation?

To multiply the variable by itself

To remove the variable from the equation

To combine the variable with constants

To get the variable alone on one side of the equation

Tags

CCSS.6.EE.B.7

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve an equation with a variable subtracted by a constant?

By subtracting the constant from both sides

By adding the constant to both sides

By multiplying both sides by the constant

By dividing both sides by the constant

Tags

CCSS.6.EE.B.7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve an equation with a variable added to a constant?

By multiplying both sides by the constant

By adding the constant to both sides

By subtracting the constant from both sides

By dividing both sides by the constant

Tags

CCSS.6.EE.B.7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the inverse operation of multiplication?

Division

Subtraction

Addition

Exponentiation

Tags

CCSS.3.OA.C.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of solving the equation -2m = 10 for m?

m = -5

m = -20

m = 20

m = 5

Tags

CCSS.6.EE.B.7

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