Solving Higher-Degree Polynomials: Synthetic Division and Rational Roots

Solving Higher-Degree Polynomials: Synthetic Division and Rational Roots

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Easy

Created by

Sophia Harris

Used 1+ times

FREE Resource

Professor Dave introduces synthetic division, a method for dividing polynomials, and explores the concept of prime polynomials. He demonstrates how to use synthetic division to find polynomial solutions and explains the rational roots test, which helps identify potential solutions. The video provides a detailed walkthrough of the synthetic division process and applies the rational roots test to solve polynomial equations.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is synthetic division primarily used for?

To multiply polynomials

To subtract polynomials

To divide polynomials

To add polynomials

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which polynomial is considered prime?

X^6 + 1

X^6 - 1

X^2 - 1

X^2 + 1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example, what does a zero remainder indicate about X=2 for the polynomial X^4 + X^3 - 11X^2 - 5X + 30?

X=2 is an exponent

X=2 is a coefficient

X=2 is a solution

X=2 is not a solution

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the degree of the polynomial after dividing by a factor like X minus two?

It increases by one

It decreases by one

It becomes zero

It remains the same

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the rational roots test help to identify?

Exact solutions for a polynomial

Potential solutions for a polynomial

Prime numbers

Coefficients of the polynomial

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a possible zero based on the rational roots test for the polynomial 2X^3 + 3X^2 - 3X - 2?

2

1

3

-1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the rational roots test generate potential solutions?

By subtracting the constant term from the leading coefficient

By creating fractions from factors of the constant term and the leading coefficient

By multiplying factors of the leading coefficient and constant term

By dividing the leading coefficient by the constant term

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?