Exploring Derivatives and Polar Coordinates

Exploring Derivatives and Polar Coordinates

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial covers polar coordinates, starting with their definition and relation to the Pythagorean identity. It progresses to differentiating in polar form and graphing polar curves, including rose curves. The tutorial explains calculating slopes of tangent lines and explores advanced topics like second derivatives and related rates in polar coordinates.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation used to convert Cartesian coordinates to polar coordinates for the x-component?

x = sin(theta)/cos(theta)

x = r tan(theta)

x = r cos(theta)

x = r sin(theta)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What trigonometric identity is primarily used when dealing with polar coordinates?

Pythagorean identity

Cosine rule

Sine rule

Tangent identity

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the Pythagorean identity in polar coordinates relate to?

The relationship between the x and y components.

The conversion between Cartesian and polar coordinates.

The relationship between r and theta.

The calculation of the radius from the origin.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of polar coordinates, what does the rose curve equation typically look like?

r = a*sin(n*theta)

r = a + sin(n*theta)

r = cos(n*theta)

r = sin(n*theta)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a key feature of the rose curve in polar coordinates?

It is defined only in the first quadrant.

It has petals equal to n when r = sin(n*theta).

It always intersects the origin.

It cannot have loops.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the derivative of a polar function typically represented?

d(r)/d(theta)

d(y)/d(x)

d(theta)/d(r)

d(x)/d(y)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct expression for the slope of the tangent line in polar coordinates?

dy/dx = r'(theta) * sin(theta) + r(theta) * cos(theta)

dy/dx = r(theta) * cos(theta) - r'(theta) * sin(theta)

dy/dx = r(theta) * sin(theta) + r'(theta) * cos(theta)

dy/dx = r'(theta) * cos(theta) - r(theta) * sin(theta)

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