Solving 2-Step Equations: Key Concepts and Techniques

The video tutorial explains how to solve two-step equations by isolating the variable. Using the example equation 7 + 5z = -18, the instructor demonstrates the process of subtracting 7 from both sides to maintain balance and then dividing by 5 to solve for Z. The solution is verified to ensure accuracy, emphasizing the importance of keeping equations balanced throughout the process.

What is the first step in solving the equation 7 + 5z = -18?

• Subtract 7 from both sides

• Add 7 to both sides

• Divide both sides by 5

• Multiply both sides by 5

Tags

CCSS.7.EE.B.4A

What is the result of subtracting 7 from -18 in the equation?

• -15

• -25

• 11

• -11

Tags

CCSS.7.NS.A.1C

Why do we subtract 7 from both sides of the equation?

• To eliminate the constant term

• To isolate the variable z

• To simplify the equation

• To balance the equation

Tags

CCSS.6.EE.B.7

After subtracting 7 from both sides, what does the equation become?

• 0 = 5z - 25

• 0 = 5z + 25

• -25 = 5z

• 25 = 5z

Tags

CCSS.HSA.REI.A.1

Why is it important to perform the same operation on both sides of the equation?

• To simplify the calculation

• To keep the equation balanced

• To make the equation more complex

• To change the equation's variables

Tags

CCSS.6.EE.B.7

What operation is performed to isolate z after subtracting 7?

• Addition

• Multiplication

• Division

• Subtraction

Tags

CCSS.HSA.REI.A.1

What does the equation 5z = -25 imply about z?

• z is 5

• z is -5

• z is 25

• z is -25

Tags

CCSS.6.EE.B.7

What is the value of z after dividing both sides by 5?

• 5

• -5

• 25

• -25

Tags

CCSS.6.EE.B.7

How do you check if z = -5 is the correct solution to the equation?

• Add 5 to z

• Subtract 5 from z

• Multiply z by -5

• Substitute z = -5 into the original equation

Tags

CCSS.6.EE.B.5

What is the purpose of dividing by 5 in the equation 5z = -25?

• To eliminate z from the equation

• To find the value of z

• To multiply the equation

• To add complexity to the equation

Tags

CCSS.6.EE.B.7