The video tutorial provides practice in solving equations involving fractions and decimals. It covers three examples: solving for J, N, and R. Each example demonstrates isolating the variable, performing arithmetic operations, and verifying the solution. The tutorial emphasizes maintaining equality by performing operations on both sides of the equation.

What is the first step in solving equations involving fractions and decimals?

• Isolate the variable

• Add fractions to both sides

• Multiply both sides by the denominator

• Subtract the constant term

Tags

CCSS.6.EE.B.7

What operation is performed to eliminate -10/3 from the equation?

• Division by 10/3

• Subtraction of 10/3

• Addition of 10/3

• Multiplication by 10/3

Tags

CCSS.HSA.REI.A.1

What is the simplified form of 9/3?

• 3

• 6

• 9

• 12

Tags

CCSS.6.EE.A.1

How do you solve for J when the equation is J/4 = 3?

• Subtract 4 from both sides

• Add 4 to both sides

• Divide both sides by 4

• Multiply both sides by 4

Tags

CCSS.6.EE.B.7

How do you verify the solution of J = 12 in the equation?

• Substitute J = 12 and check if both sides are equal

• Multiply both sides by 12

• Divide both sides by 12

• Add 12 to both sides

Tags

CCSS.6.EE.B.5

What is the result of subtracting 0.6 from both sides of the equation involving N?

• N/5 = 1.4

• N/5 = 2.6

• N/5 = 0.6

• N/5 = 2.0

Tags

CCSS.6.EE.B.7

What value of N satisfies the equation N/5 + 0.6 = 2?

• 1.4

• 5

• 7

• 2.6

Tags

CCSS.7.EE.B.4A

How is the equation 0.5 * (R + 2.75) = 3 simplified?

• Multiply both sides by 0.5

• Add 0.5 to both sides

• Subtract 0.5 from both sides

• Divide both sides by 0.5

Tags

CCSS.7.EE.B.4A

After dividing both sides of the equation by 0.5, what is the new form of the equation for R?

• R + 2.75 = 6

• R + 2.75 = 3

• R + 2.75 = 12

• R + 2.75 = 0.5

Tags

CCSS.HSA.REI.A.1

What is the final value of R when 2.75 is subtracted from both sides?

• 3

• 3.25

• 2.75

• 6

Tags

CCSS.6.EE.B.7