Factoring Trinomials with a Common Factor

Factoring Trinomials with a Common Factor

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to factor the expression 8k^2 - 24k - 144. It begins by identifying that all terms are divisible by 8, simplifying the expression to 8(k^2 - 3k - 18). The tutorial then focuses on factoring the quadratic expression by finding two numbers whose sum is -3 and product is -18, which are 3 and -6. The expression is further simplified using grouping, resulting in the final factored form: 8(k + 3)(k - 6).

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the greatest common factor of the terms in the expression 8k^2 - 24k - 144?

2

4

24

8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After factoring out the greatest common factor, what is the simplified form of the expression?

k^2 - 3k - 18

8(k^2 - 3k - 18)

8(k^2 - 3k + 18)

k^2 - 3k + 18

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which operation is performed to simplify the expression 8(k^2 - 3k - 18)?

Multiplication

Subtraction

Addition

Division

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which pair of numbers has a sum of -3 and a product of -18?

3 and 6

-3 and 6

-3 and -6

3 and -6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of factoring by grouping, which term is used to split the middle term of the quadratic expression?

3k - 6k

3k + 6k

-3k + 6k

-3k - 6k

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the factored form of the expression inside the brackets after applying the grouping method?

(k - 6)(k + 3)

(k + 3)(k - 6)

(k - 3)(k + 6)

(k + 6)(k - 3)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What common factor is factored out from the grouped terms in the expression?

k + 6

k - 6

k - 3

k + 3

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