Solving Literal Equations and Operations

Solving Literal Equations and Operations

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Medium

Created by

Olivia Brooks

Used 6+ times

FREE Resource

In this video, Burns's Math Club teaches how to solve literal equations, a topic many students find challenging. The video explains that solving literal equations involves isolating a variable rather than finding its value. Two examples are provided: 'ax + b = c' and '2x + 3y = 6', both solved for x. The process involves using inverse operations to isolate the variable. The video emphasizes understanding the steps to simplify the process and concludes with a summary of the key points.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a common challenge students face with literal equations?

Understanding the concept of variables

Dealing with inverse operations

Performing basic arithmetic

Memorizing formulas

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation ax + b = c for x?

Subtract b from both sides

Divide both sides by a

Add b to both sides

Multiply both sides by a

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation ax + b = c, what operation is used to isolate x after subtracting b?

Addition

Division

Subtraction

Multiplication

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final form of x in the equation ax + b = c?

x = (c + b) / a

x = (c - b) / a

x = c - b / a

x = c + b / a

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation 2x + 3y = 6, what is the first step to isolate x?

Add 3y to both sides

Subtract 3y from both sides

Multiply both sides by 2

Divide both sides by 2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After subtracting 3y from both sides in the equation 2x + 3y = 6, what is the next step?

Subtract 2 from both sides

Multiply both sides by 2

Divide both sides by 2

Add 2 to both sides

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplified form of x in the equation 2x + 3y = 6?

x = 6 / 2 - 3y

x = 6 / 2 + 3y

x = (6 - 3y) / 2

x = (6 + 3y) / 2

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