Logarithmic and Exponential Equations

Logarithmic and Exponential Equations

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

CCSS
HSF.BF.B.5, HSF.LE.A.4

Standards-aligned

Created by

Mia Campbell

FREE Resource

Standards-aligned

CCSS.HSF.BF.B.5
,
CCSS.HSF.LE.A.4
This video tutorial covers solving equations in exponential and logarithmic forms. It begins with an introduction to the concepts, followed by detailed methods for solving exponential and logarithmic equations. The tutorial includes advanced problem-solving techniques and practical applications, such as financial calculations involving compound interest. The video emphasizes the importance of understanding the base and exponent relationships and using calculators for complex calculations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation 3^x = 81?

Divide both sides by 3

Convert the equation to logarithmic form

Change 81 to a base of 3

Use a calculator to find the value of x

Tags

CCSS.HSF.BF.B.5

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If e^x = 13, what is the logarithmic form of this equation?

log_10(13) = x

log(13) = x

ln(13) = x

log_e(13) = x

Tags

CCSS.HSF.BF.B.5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve the equation ln(x) = 5?

Divide both sides by ln

Convert to exponential form: e^5 = x

Convert to logarithmic form: log_e(x) = 5

Use a calculator to find ln(5)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the solution to the equation 10^-3 = x?

x = -1000

x = 1/10

x = 1000

x = 1/1000

Tags

CCSS.HSF.BF.B.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When solving e^(2x) = 12, what is the first step?

Convert to logarithmic form

Divide both sides by 2

Subtract 12 from both sides

Factor the equation

Tags

CCSS.HSF.BF.B.5

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the solution to the equation e^x = 3?

x = e^3

x = 3

x = ln(3)

x = 1/3

Tags

CCSS.HSF.BF.B.5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't you take the natural log of a negative number?

Because the domain of the natural log function is x > 0

Because it is undefined

Because it results in zero

Because it results in a complex number

Tags

CCSS.HSF.LE.A.4

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