Solving Quadratic Equations Using Square Roots

What is the first step in solving a quadratic equation by working from the outside in?

• Add 20 to both sides

• Divide by the coefficient of x^2

• Subtract 20 from both sides

• Take the square root of both sides

Tags

CCSS.HSA-REI.B.4B

What do you get when you divide both sides by 6 in the equation provided?

• x^2 = 4

• x^2 = 6

• 6x^2 = 24

• x^2 = 24

Tags

CCSS.HSA-REI.B.4B

What are the solutions when you take the square root of both sides?

• +2 and -2

• +4 and -4

• 0

• No solution

What happens when you try to take the square root of a negative number in an equation?

• The equation simplifies further

• You get an imaginary number

• You get two positive solutions

• You get a real number

Tags

CCSS.HSA.REI.A.2

What is the correct statement about the solution for an equation with a square root of a negative number?

• There are two real solutions

• There is one real solution

• There is no real solution

• There are infinitely many solutions

Tags

CCSS.8.EE.A.2

In the complex equation, what is the first step to isolate x?

• Add 3

• Divide by 2

• Subtract 4

• Take the square root

Tags

CCSS.HSA-REI.B.4B

After dividing by 2 in the complex equation, what operation is performed next?

• Multiplication

• Taking the square root

• Addition

• Subtraction

Tags

CCSS.8.EE.A.2

What is the result after taking the square root in the complex equation?

• x - 3 = ±5

• x + 3 = 5

• x + 3 = ±5

• x - 3 = 5

Tags

CCSS.8.EE.A.2

How do you find the final solutions in the complex equation?

• Divide both sides by 3

• Add 3 to both sides

• Multiply both sides by 3

• Subtract 3 from both sides

Tags

CCSS.HSA-REI.B.4B

What are the final solutions for the complex equation?

• 3 and -3

• 5 and -5

• 8 and -2

• 10 and 0

Tags

CCSS.HSA-REI.B.4B