Multi-Step Multiplication and Division Challenge for 4th Graders

The video tutorial introduces a multi-step math problem involving multiplication and division. Gianna saves $7 weekly for 16 weeks to buy $3 paint brushes. The tutorial guides viewers through calculating her total savings and using division to determine how many brushes she can buy, explaining the remainder as leftover money. The video emphasizes understanding multi-step problems and visualizing calculations.

How many weeks has Gianna been saving her money?

• 24 weeks

• 12 weeks

• 7 weeks

• 16 weeks

Tags

CCSS.3.OA.A.3

What is the cost of one paint brush?

• $2

• $5

• $3

• $4

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CCSS.3.OA.A.3

What is the first step in solving Gianna's problem?

• Multiply her weekly savings by the number of weeks

• Divide her savings by the cost of one paint brush

• Add the cost of all paint brushes together

• Subtract the cost of a paint brush from her savings

Tags

CCSS.4.OA.A.3

What mathematical operations are used in solving the problem?

• Division and addition

• Multiplication and subtraction

• Addition and subtraction

• Multiplication and division

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CCSS.3.OA.D.8

How much total money did Gianna save?

• $95

• $100

• $112

• $120

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CCSS.6.NS.B.3

How is Gianna's total savings calculated?

• Adding 7 to itself 16 times

• Multiplying 7 by 16

• Dividing 7 by 16

• Subtracting 7 from 16

Tags

CCSS.3.OA.A.1

How many paint brushes can Gianna buy?

• 38

• 36

• 37

• 35

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CCSS.3.OA.A.3

What does Gianna do with the remainder of her savings?

• Donates it

• It is not mentioned

• Saves it for later

• Buys more paint

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CCSS.RI.1.4

CCSS.RI.2.1

CCSS.RI.3.1

CCSS.RL.2.1

CCSS.RL.3.1

How much money does Gianna have left after her purchase?

• No money left

• $3

• $2

• $1

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CCSS.5.NBT.B.7

What is the purpose of dividing Gianna's savings by the cost of a paint brush?

• To determine how many brushes she can buy

• To calculate the total cost of brushes

• To subtract the total cost from her savings

• To find out how many brushes she can't buy

Tags

CCSS.3.OA.A.2