Balancing Combustion Reactions and Molar Mass

Balancing Combustion Reactions and Molar Mass

Assessment

Interactive Video

Chemistry, Science

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

This video tutorial covers the practice problems for lesson 9, focusing on balancing chemical equations and solving three related problems. The first problem involves calculating the volume of CO2 produced from burning butane in excess oxygen. The second problem converts the volume of oxygen gas to the volume of CO2 gas. The third problem calculates the mass of CO2 produced from a given volume of butane gas. The tutorial emphasizes the use of molar mass, mole ratios, and gas volume conversions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step recommended for balancing combustion reactions?

Start with hydrogen on the left side

Begin with water on the right side

Begin with oxygen on the left side

Start with carbon dioxide on the right side

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it suggested to multiply everything by a factor of 2 when balancing the equation?

To decrease the number of oxygen atoms

To increase the number of hydrogen atoms

To eliminate odd numbers

To simplify the equation

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first problem, what is the known quantity?

Volume of oxygen

Mass of butane

Volume of CO2

Mass of water

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of butane used in the first problem?

58.44 g/mol

16.04 g/mol

44.01 g/mol

32.00 g/mol

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second problem, what is the known quantity?

Mass of water

Volume of CO2

Volume of oxygen

Mass of butane

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mole ratio of O2 to CO2 in the second problem?

2:8

8:2

8:13

13:8

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the third problem, what is the known quantity?

Mass of water

Volume of oxygen

Mass of CO2

Volume of butane

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