What is the first step in solving a quadratic equation by completing the square?

Quadratic Equation: Completing the Square

Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Hard

Sophia Harris
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Move the constant term to the right side of the equation.
Add a constant to both sides.
Multiply all terms by the leading coefficient.
Take the square root of both sides.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do we divide all terms by the leading coefficient when completing the square?
To simplify the constant on the right side.
To eliminate the constant term.
To ensure the leading coefficient is 1.
To make the equation easier to solve.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the constant needed to complete the square?
Add the coefficient of x to the constant term.
Multiply the coefficient of x by 2 and square it.
Divide the coefficient of x by 2 and square it.
Subtract the constant term from the coefficient of x.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of factoring the trinomial in the process of completing the square?
To find the roots of the equation.
To simplify the equation.
To eliminate the x term.
To express it as a product of binomials.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What must be done after factoring the trinomial to solve for x?
Add the constant to both sides.
Multiply both sides by the leading coefficient.
Take the square root of both sides.
Subtract the constant from both sides.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it necessary to include a plus or minus sign when taking the square root of both sides?
To account for both positive and negative roots.
To ensure the equation is balanced.
To simplify the equation.
To eliminate the constant term.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final form of the solution for x in this method?
x equals a fraction with a square root.
x equals a constant.
x equals a binomial squared.
x equals a trinomial.
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