Isolating Variables in Equations

This video tutorial covers solving and rearranging literal equations, which involve multiple variables representing real values. It explains one-step and multi-step rearranging processes, translating word problems into equations, and provides practice problems to reinforce learning. The tutorial emphasizes understanding the operations needed to isolate variables and solve equations effectively.

What is a literal equation?

• An equation with no variables

• An equation with several variables representing values

• An equation that cannot be solved

• An equation with only one variable

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CCSS.HSA.REI.B.3

In the equation A = L * W, what does solving for W involve?

• Subtracting L from both sides

• Adding L to both sides

• Multiplying both sides by L

• Dividing both sides by L

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CCSS.HSA.CED.A.4

How do you isolate R in the equation 4R - B = M?

• Divide both sides by 4, then subtract B

• Add B to both sides, then divide by 4

• Subtract B from both sides, then multiply by 4

• Multiply both sides by 4, then add B

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CCSS.HSA.REI.A.1

What is the first step in solving for W in the equation P = 2(L + W)?

• Add L to both sides

• Divide both sides by 2

• Multiply both sides by 2

• Subtract L from both sides

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CCSS.HSA.CED.A.4

In the formula V = 1/3 * B * H, how do you solve for H?

• Multiply both sides by B

• Divide both sides by B

• Multiply both sides by 3

• Subtract B from both sides

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CCSS.HSA.CED.A.4

How do you isolate B1 in the equation A = 1/2 * H * (B1 + B2)?

• Subtract B2 from both sides, then divide by 2

• Add B2 to both sides, then multiply by 2

• Divide both sides by 2, then add B2

• Multiply both sides by 2, then subtract B2

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CCSS.7.EE.B.4A

What operation is needed to isolate Y in the equation Y = 2X + 5?

• Multiply both sides by 2

• Subtract 2X from both sides

• Divide both sides by 5

• Add 5 to both sides

Tags

CCSS.HSA.REI.B.3

In the equation 3Y = 6X + 9, what is the first step to solve for Y?

• Subtract 6X from both sides

• Divide both sides by 3

• Add 9 to both sides

• Multiply both sides by 3

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CCSS.6.EE.C.9

How do you solve for Y in the equation 4Y - 2X = 8?

• Add 2X to both sides, then divide by 4

• Subtract 2X from both sides, then multiply by 4

• Divide both sides by 4, then subtract 2X

• Multiply both sides by 4, then add 2X

Tags

CCSS.6.EE.C.9

What is the result of solving for Y in the equation -2Y = -5X + 10?

• Y = -5/2X - 5

• Y = 5/2X + 5

• Y = -5/2X + 5

• Y = 5/2X - 5

Tags

CCSS.6.EE.C.9