Arc Length and Integral Evaluation

Arc Length and Integral Evaluation

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to find the arc length of a curve defined by a vector function over a closed interval. It begins with a graphical representation of the curve and vectors, followed by the introduction of the arc length formula. The tutorial then demonstrates the calculation of derivatives using the chain rule, setting up and simplifying the integral for arc length, and performing integration using substitution. The final section covers the calculation of the exact arc length, providing a comprehensive understanding of the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of finding the arc length in this problem?

To find the area under the curve

To determine the distance between two points on a curve

To identify the slope of the curve

To calculate the volume of the curve

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial interval for the arc length calculation?

From 0 to 1

From 0 to natural log 3

From 1 to 3

From natural log 3 to 0

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which mathematical rule is used to find the derivatives of the vector components?

Chain Rule

Product Rule

Power Rule

Quotient Rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of X(t) in the vector function?

5e^4t

20e^4t

4e^4t

8e^4t

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression under the square root in the arc length integral?

Sum of the squares of the derivatives

Product of the derivatives

Difference of the squares of the derivatives

Sum of the derivatives

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression under the square root simplified?

By factoring out common terms

By using logarithmic properties

By expanding the terms

By using properties of exponents

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used to evaluate the integral?

U = 4T

U = e^T

U = ln(T)

U = T^2

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