Laplace Transforms and Properties

Laplace Transforms and Properties

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to find the Laplace transform of a function using the shifting property. It begins by introducing the Laplace transform and the shifting property, then analyzes the given function to determine the necessary variables. A change of variables is performed to align the function with the shifting property. The tutorial then calculates the Laplace transform using a table of transforms, concluding with a summary of the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of the problem discussed in the video?

To solve a differential equation

To find the Laplace transform of a given function

To calculate the integral of a function

To find the derivative of a function

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which property is used to find the Laplace transform in this problem?

Initial value theorem

Convolution property

Shifting property

Linearity property

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'a' in the given function?

1

3

2

0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is a new variable introduced in the problem?

To solve a differential equation

To find the derivative of the function

To convert the function into a suitable form for the shifting property

To simplify the function for integration

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the new variable introduced in the problem?

Tau

Beta

Gamma

Alpha

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for F(Tau) derived in the video?

Tau plus one

Tau squared plus two Tau

Tau squared plus two Tau plus one

Tau squared

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is F(Tau - 1) related to the original function?

It is unrelated to the original function

It is the derivative of the original function

It is the integral of the original function

It is the same as the original function

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