Solving Linear Equations and Inequalities

Solving Linear Equations and Inequalities

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Practice Problem

Hard

CCSS
6.EE.A.2C, 6.EE.B.7

Standards-aligned

Created by

Liam Anderson

FREE Resource

Standards-aligned

CCSS.6.EE.A.2C
,
CCSS.6.EE.B.7
The video tutorial explains how to solve a system of equations. It starts by solving the equation x divided by 3 equals 5, resulting in x equals 15. Then, it substitutes this value into the second equation, x plus y equals 42, to find y equals 27. Finally, it calculates x minus y, which equals negative 12.

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step to solve the equation x divided by 3 equals 5?

Divide both sides by 5

Subtract 5 from both sides

Multiply both sides by 3

Add 3 to both sides

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If x equals 15, what equation can be used to find y given x plus y equals 42?

y minus 15 equals 42

x plus 15 equals 42

x minus y equals 42

15 plus y equals 42

Tags

CCSS.6.EE.B.7

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for y in the equation 15 plus y equals 42?

Add 15 to both sides

Multiply both sides by 15

Subtract 15 from both sides

Divide both sides by 15

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of y if x equals 15 and x plus y equals 42?

42

57

27

15

Tags

CCSS.6.EE.A.2C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of x minus y if x equals 15 and y equals 27?

12

42

-12

-42

Tags

CCSS.6.EE.A.2C

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