Differential Equations and Their Solutions

Differential Equations and Their Solutions

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains how to solve a differential equation using the method of substitution. It begins by discussing different types of equations and why the given equation is not homogeneous. The tutorial then introduces a substitution method to simplify the equation, transforming it into a separable form. After solving the separable equation through integration, the solution is back-substituted to find the general solution. The tutorial concludes by discussing the implications of having two solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following methods is NOT mentioned as a substitution method for solving differential equations?

General substitutions

Bernoulli equations

Laplace transforms

Homogeneous equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the given differential equation not considered homogeneous?

It is already solved

It has a constant term

It involves exponential functions

It cannot be written in the form of y' = f(y)/x

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is introduced to simplify the differential equation?

V = y/x

V = y - x

V = y^2 - x^2

V = y^2 + x^2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the form of the separable differential equation after substitution?

e^V = V'

V' = e^V

V' = V

V = e^V

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What technique is used to integrate the differential equation?

Partial fraction decomposition

Integration by parts

Trigonometric substitution

U substitution

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for V after solving the integrated equation?

V = -ln(C - x)

V = ln(C - x)

V = ln(x - C)

V = -ln(x + C)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the equation rewritten in terms of x and y?

y^2 = ln(x - C) - x^2

y^2 = ln(C - x) - x^2

y^2 = x^2 - ln(C - x)

y^2 = x^2 + ln(C - x)

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