Inclusion-Exclusion Principle in Permutations

Inclusion-Exclusion Principle in Permutations

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to find permutations of six elements where exactly one element remains fixed. The strategy involves selecting one element to be fixed and calculating the derangements of the remaining five elements using the principle of inclusion-exclusion. The process includes calculating permutations, subtracting non-derangements, and adjusting for over-subtraction by adding and subtracting combinations of fixed elements. The final result is 264 permutations that meet the criteria.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main problem discussed in the video?

Finding permutations with no elements fixed

Finding permutations with two elements fixed

Finding permutations with all elements fixed

Finding permutations with exactly one element fixed

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the problem?

Subtracting non-derangements

Finding the number of permutations of all elements

Selecting one element to be fixed

Calculating the factorial of six

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do we calculate the number of derangements for the remaining elements?

By finding the factorial of the remaining elements

By multiplying the number of permutations

By adding the number of fixed elements

By using the principle of inclusion-exclusion

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of subtracting non-derangements with at least one element fixed?

To simplify the calculation

To adjust for overcounting in derangements

To ensure no elements are fixed

To find the total number of permutations

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of adding back non-derangements with at least two elements fixed?

It decreases the total permutations

It has no effect

It increases the total permutations

It corrects the over-subtraction

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we subtract non-derangements with at least three elements fixed?

To correct for over-addition

To simplify the calculation

To find the number of permutations

To ensure all elements are fixed

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of five choose four times one factorial in the calculation?

It represents the number of ways to fix two elements

It represents the number of ways to fix three elements

It represents the number of ways to fix four elements

It represents the number of ways to fix all elements

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?