Understanding Recurrence Relations and Characteristic Equations

Understanding Recurrence Relations and Characteristic Equations

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Sophia Harris

FREE Resource

This video tutorial explains how to solve recurrence relations using the characteristic root technique. It covers both distinct and repeated solutions of characteristic equations. An example problem is presented, demonstrating the process of setting up and solving a recurrence relation with given initial conditions. The tutorial emphasizes the difference in solutions when dealing with repeated roots, highlighting the presence of an 'n' factor in the general solution. Key points are summarized to reinforce understanding.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the form of the characteristic equation for a recurrence relation of the form a_n + αa_(n-1) + βa_(n-2) = 0?

x^2 + αx + β = 0

x^2 - αx + β = 0

x^2 - αx - β = 0

x^2 + αx - β = 0

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When the characteristic equation has two distinct roots, what is the form of the solution to the recurrence relation?

a_n = a * r_1^n + b * r_2^n

a_n = a * n * r^n + b * r^n

a_n = a * r^n + b * n * r^n

a_n = a * r^n + b * r^n

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What additional factor appears in the solution when the characteristic equation has a repeated root?

A factor of n^4

A factor of n^2

A factor of n

A factor of n^3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example problem, what are the values of α and β for the recurrence relation a_n = 8a_(n-1) - 16a_(n-2)?

α = 8, β = -16

α = -8, β = 16

α = -8, β = -16

α = 8, β = 16

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the repeated root of the characteristic equation x^2 - 8x + 16 = 0?

x = 2

x = 16

x = 4

x = 8

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the form of the general solution for the example problem with a repeated root?

a_n = a * 4^n + b * n * 4^n

a_n = a * 4^n + b * 4^n

a_n = a * 4^n + b * n^2 * 4^n

a_n = a * n * 4^n + b * 4^n

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Using the initial condition a_0 = 1, what is the value of constant A in the general solution?

A = 4

A = 2

A = 1

A = 0

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