Understanding Tangent Lines and Derivatives

Understanding Tangent Lines and Derivatives

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to find the equation of a tangent line to the graph of a function at a specific point. It begins by identifying the need for both a point and the slope of the tangent line. The derivative of the function is calculated using the chain rule, and then evaluated at the given point to find the slope. The equation of the tangent line is derived in both point-slope and slope-intercept forms. Finally, the tutorial provides a graphical representation of the function and its tangent line.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of the problem discussed in the video?

To find the area under the curve

To determine the equation of the tangent line

To calculate the integral of the function

To solve a differential equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the inner function in the composite function f(x) = (2/3) * sin(sin(x))?

cos(x)

sin(x)

tan(x)

x^2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the derivative of the inner function, sin(x), expressed?

cos(x)

sec(x)

tan(x)

sin(x)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the derivative function at x = 2π?

0

2/3

1

4/3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the slope of the tangent line at the point (2π, 0)?

3/2

2/3

1

0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In point-slope form, what is the equation of the tangent line?

y - 0 = 2/3(x - 2π)

y = 2/3x - 4/3π

y = 2/3x + 4/3π

y = x - 2π

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the equation of the tangent line expressed in slope-intercept form?

y = x - 2π

y = 2/3x

y = 2/3x - 4/3π

y = 2/3x + 4/3π

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