Maximizing Area of Rectangles

Maximizing Area of Rectangles

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains how to find the dimensions of a rectangle with a fixed perimeter of 1,760 cm that maximizes the area. It involves setting up equations for perimeter and area, solving for one variable, and using a quadratic function to find the maximum area. The solution reveals that the rectangle is a square with sides of 440 cm, resulting in a maximum area of 193,600 cm².

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the perimeter of the rectangle given in the problem?

1,760 cm

1,800 cm

1,700 cm

1,750 cm

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation represents the perimeter of the rectangle?

2L + 2W = 1,760

L + W = 1,760

L * W = 1,760

2L + W = 1,760

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the area of the rectangle expressed in terms of one variable?

A = L * (880 - L)

A = W * (880 - W)

A = L + W

A = 2L + 2W

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What shape does the graph of the area function take?

A circle

A straight line

A parabola opening downwards

A parabola opening upwards

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the vertex in the graph of the area function?

It represents the perimeter.

It represents the average area.

It represents the maximum area.

It represents the minimum area.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the length of the rectangle when the area is maximized?

440 cm

660 cm

880 cm

220 cm

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the maximum area of the rectangle?

19,000 cm²

19,500 cm²

19,300 cm²

19,600 cm²

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