Understanding the Intersection of Planes

Understanding the Intersection of Planes

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to find the equation of the line formed by the intersection of two planes. It covers the identification of normal vectors for each plane, the use of cross product to determine the directional vector, and the algebraic method to find a point on the line. Finally, it formulates the line equation in parametric form and as a vector-valued function.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the normal vector to the plane given by the equation x + 2y - 4z = 16?

(1, 2, -4)

(2, -1, 3)

(1, -2, 4)

(2, 1, -3)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is necessary to write the parametric equations of a line in space?

A normal vector and a direction vector

A point on the line and a normal vector

A point on the line and a direction vector

Two points on the line

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the cross product of two normal vectors?

A point on the line

The normal vector to the line

The directional vector of the line

The equation of the line

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find a point on the line of intersection of two planes?

By finding the midpoint of the planes

By solving the system of equations derived from the planes

By taking the average of the normal vectors

By using the cross product of the normal vectors

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of z when x is set to zero in the system of equations derived from the planes?

16

14

12

18

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-coordinate of the point on the line of intersection when x is zero?

36

28

14

42

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the parametric equations for the line of intersection?

x(t) = 2t, y(t) = 36 - 5t, z(t) = 14 - 11t

x(t) = 2t, y(t) = 36 - 11t, z(t) = 14 - 5t

x(t) = 2t, y(t) = 36 + 11t, z(t) = 14 + 5t

x(t) = 2t, y(t) = 11t - 36, z(t) = 5t - 14

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