
Midpoint Rule in Numerical Integration

Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Hard
Standards-aligned

Mia Campbell
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of using the midpoint rule in numerical integration?
To approximate the value of a definite integral
To determine the derivative of a function
To find the exact value of the integral
To solve differential equations
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the width of each subinterval calculated in the midpoint rule?
By dividing the total interval by the number of subintervals
By adding the limits of integration
By multiplying the total interval by the number of subintervals
By subtracting the limits of integration
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the midpoint in each subinterval?
It is the average of the function values at the endpoints
It determines the width of the rectangle
It is the point where the function is zero
It is used to find the function value for the height of the rectangle
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can some areas be considered negative in the midpoint rule?
Because the midpoint is negative
Because the function value is positive
Because the function value is negative
Because the width of the subinterval is negative
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the formula used in the midpoint rule to approximate the integral?
Sum of function values at endpoints times width
Sum of function values at midpoints times width
Product of function values at midpoints and endpoints
Difference of function values at midpoints and endpoints
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you find the midpoint of a subinterval?
By averaging the endpoints of the subinterval
By subtracting the endpoints of the subinterval
By multiplying the endpoints of the subinterval
By dividing the endpoints of the subinterval
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the function used in the example to approximate the integral?
x^2 + 2x
x^2 - 2x
x^3 + 3x
x^3 - 3x
Tags
CCSS.8.F.B.4
CCSS.HSF.IF.B.6
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