Differential Equations Verification Process

Differential Equations Verification Process

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

CCSS
HSA.REI.A.1, 8.EE.C.7B, HSA-REI.B.4B

Standards-aligned

Created by

Amelia Wright

FREE Resource

Standards-aligned

CCSS.HSA.REI.A.1
,
CCSS.8.EE.C.7B
,
CCSS.HSA-REI.B.4B
The video tutorial explains how to find and verify the general solution of a linear second order homogeneous differential equation with constant coefficients. It begins by identifying the type of differential equation and solving the characteristic equation. The process involves factorization to find distinct real roots, which determine the form of the general solution. The tutorial then demonstrates how to verify the solution by calculating derivatives and substituting them back into the original equation to ensure the left side equals zero.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of differential equation is being solved in the video?

Linear third-order with constant coefficients

Non-linear second-order with constant coefficients

Linear second-order with constant coefficients

Linear first-order with variable coefficients

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the characteristic equation derived from the given differential equation?

r^2 + 2r + 3 = 0

r^2 - r + 2 = 0

2r^2 + r - 3 = 0

3r^2 + 2r - 1 = 0

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the roots of the characteristic equation?

r = 1/2 and r = -3

r = 3/2 and r = -1

r = -3/2 and r = 1

r = 2 and r = -1/2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which form of the general solution is used for two distinct real roots?

y = c1 * e^(ax) + c2 * e^(-ax)

y = (c1 + c2 * x) * e^(r * x)

y = c1 * e^(r1 * x) + c2 * e^(r2 * x)

y = c1 * cos(bx) + c2 * sin(bx)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first derivative of the general solution?

y' = c1 * e^(-3x/2) + c2 * e^x

y' = 3c1 * e^(3x/2) - c2 * e^x

y' = -c1 * e^(3x/2) + c2 * e^x

y' = -3c1 * e^(-3x/2) + c2 * e^x

Tags

CCSS.HSA.REI.A.1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the second derivative of the general solution?

y'' = 9c1 * e^(3x/2) - c2 * e^x

y'' = 9c1 * e^(-3x/2) + c2 * e^x

y'' = -9c1 * e^(-3x/2) + c2 * e^x

y'' = 9c1 * e^(-3x/2) - c2 * e^x

Tags

CCSS.HSA-REI.B.4B

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of substituting the derivatives back into the original equation?

To find new roots

To simplify the equation

To determine the coefficients

To verify the solution

Tags

CCSS.HSA.REI.A.1

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