Understanding Quadratic Functions

Understanding Quadratic Functions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to convert a quadratic function from general form to standard form. It covers the process of creating a perfect square trinomial, identifying the vertex and axis of symmetry, and graphing the parabola. The tutorial also demonstrates finding additional points for a more accurate graph and emphasizes the symmetry of the parabola.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the parabola if the coefficient 'A' in the standard form is greater than zero?

The parabola becomes a straight line.

The parabola opens upwards.

The parabola does not change.

The parabola opens downwards.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in converting a quadratic equation to standard form?

Multiply the equation by a constant.

Subtract a constant from both sides.

Isolate the x-squared and x terms.

Add a constant to both sides.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the constant to add when completing the square?

Square the coefficient of x.

Take half of the coefficient of x and square it.

Take the square root of the coefficient of x.

Double the coefficient of x.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex of the parabola given by the equation y = (x + 1)^2 - 5?

(1, 5)

(-1, -5)

(1, -5)

(-1, 5)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the axis of symmetry for the parabola y = (x + 1)^2 - 5?

y = 1

x = -1

x = 1

y = -1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-intercept of the parabola in the original equation form?

(0, 0)

(0, 4)

(0, -5)

(0, -4)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you find additional points on the parabola for a more accurate graph?

By finding the x-intercepts.

By using only the vertex.

By drawing random points.

By evaluating the function at different x values.

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