Understanding One-Step Linear Equations

The video tutorial explains how to solve one-step linear equations where the variable is on the right side. It demonstrates the process of isolating the variable by performing opposite operations on both sides of the equation. Two examples are provided: one involving addition and the other involving subtraction. The tutorial emphasizes rewriting equations in the form of 'x equals some number' and checking solutions by substituting back into the original equation.

What is the main goal when solving one-step linear equations?

• To make both sides of the equation equal

• To isolate the variable

• To eliminate all numbers

• To multiply both sides by zero

Tags

CCSS.6.EE.B.7

In the equation 17 = x + 14, what operation should be performed to isolate x?

• Multiply both sides by 14

• Subtract 14 from both sides

• Add 14 to both sides

• Divide both sides by 14

Tags

CCSS.6.EE.B.7

What is the solution to the equation 17 = x + 14?

• x = 3

• x = 31

• x = 14

• x = 17

Tags

CCSS.1.NBT.C.4

CCSS.2.MD.B.6

What is the opposite operation of addition?

• Subtraction

• Multiplication

• Division

• Exponentiation

Tags

CCSS.6.EE.B.5

How can you verify the solution to the equation 17 = x + 14?

• By checking if 17 equals 3 plus 14

• By checking if 17 equals 14 minus 3

• By checking if 17 equals 3 times 14

• By checking if 17 equals 14 divided by 3

Tags

CCSS.6.EE.B.7

In the equation 23 = x - 5, what operation should be performed to isolate x?

• Add 5 to both sides

• Divide both sides by 5

• Subtract 5 from both sides

• Multiply both sides by 5

Tags

CCSS.6.EE.B.7

What is the solution to the equation 23 = x - 5?

• x = 5

• x = 23

• x = 18

• x = 28

Tags

CCSS.6.NS.B.3

What is the opposite operation of subtraction?

• Addition

• Multiplication

• Division

• Exponentiation

Tags

CCSS.6.EE.B.5

How can you verify the solution to the equation 23 = x - 5?

• By checking if 23 equals 5 plus 28

• By checking if 23 equals 5 divided by 28

• By checking if 23 equals 28 times 5

• By checking if 23 equals 28 minus 5

Tags

CCSS.6.EE.B.7

Why is it important to perform the same operation on both sides of an equation?

• To change the equation's solution

• To eliminate the variable

• To make the equation more complex

• To keep the equation balanced

Tags

CCSS.6.EE.B.7