
Complex Solutions and Factoring Techniques

Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Hard
Standards-aligned

Emma Peterson
FREE Resource
Standards-aligned
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5 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the limitation of taking the fourth root of both sides of the equation x^4 = 16?
It only provides two solutions.
It results in no solutions.
It provides three solutions.
It gives all four solutions.
Tags
CCSS.HSA-REI.B.4B
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving the equation by factoring?
Divide both sides by 4.
Multiply both sides by 4.
Add 16 to both sides.
Subtract 16 from both sides.
Tags
CCSS.HSA-REI.B.4B
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is a real solution obtained from factoring the equation?
x = 3
x = 2
x = -3
x = 4
Tags
CCSS.HSA-REI.B.4B
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you find the complex solutions after factoring?
By setting x^2 - 4 equal to zero.
By setting x^2 + 4 equal to zero.
By setting x^2 - 16 equal to zero.
By setting x^2 + 16 equal to zero.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the complex solutions to the equation x^2 + 4 = 0?
x = ±2
x = ±4i
x = ±2i
x = ±i
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