What is the issue encountered when trying to evaluate the limit at the point (5, 11)?

Understanding Limits and Algebraic Techniques

Interactive Video
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Mathematics
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10th - 12th Grade
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Hard

Jackson Turner
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The numerator becomes zero.
The denominator becomes zero.
The function is undefined.
Both numerator and denominator become zero.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can't the limit be found using direct substitution initially?
The function is already simplified.
The function is not defined at the point.
The function is continuous.
The function is linear.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What algebraic technique is suggested to find the limit?
Completing the square
Factoring the expression
Differentiation
Using the quadratic formula
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What formula is used to factor the numerator in this problem?
Difference of cubes
Difference of squares
Quadratic formula
Sum of cubes
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the values of 'a' and 'b' in the difference of cubes formula for this problem?
a = 5, b = 11
a = x, b = y
a = x - 8, b = y - 14
a = x + 8, b = y + 14
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the common factor in the numerator and denominator?
It is multiplied by itself.
It is divided by the denominator.
It is added to the numerator.
It is canceled out.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of finding a common factor in the numerator and denominator?
It increases the function's degree.
It changes the function's domain.
It allows for simplification of the function.
It helps in finding the derivative.
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