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Implicit Differentiation and Chain Rule

Implicit Differentiation and Chain Rule

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to find dy/dx using implicit differentiation. It begins by rewriting the given equation using negative exponents. The process of differentiating both sides of the equation with respect to x is demonstrated, applying the chain rule for terms involving y. The tutorial then shows how to solve for dy/dx and concludes by expressing the derivative using positive exponents.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in implicit differentiation according to the video?

Solving for dy/dx

Applying the chain rule

Rewriting terms using positive exponents

Rewriting terms using negative exponents

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the term 2/x rewritten using negative exponents?

2x^-1

x^2

2x^1

2x^2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus when differentiating both sides of the equation with respect to x?

Only differentiate x terms

Differentiate y terms with respect to x directly

Differentiate y terms with respect to y and multiply by dy/dx

Ignore y terms

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What rule is applied when differentiating y terms with respect to x?

Product rule

Power rule

Quotient rule

Chain rule

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of differentiating the constant 1 with respect to x?

0

dy/dx

x

1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After applying the chain rule, what is the next step in solving for dy/dx?

Subtract terms from both sides

Divide both sides by negative three y to the power of negative two

Add terms to both sides

Multiply both sides by 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression for dy/dx simplified using positive exponents?

By adding exponents

By moving x terms to the denominator and y terms to the numerator

By moving y terms to the denominator

By moving x terms to the numerator

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