Understanding Equivalent Equations

This video tutorial explains how to construct equivalent equations using given operations and variable values. It covers two examples: one with x=4 and another with x=7, demonstrating operations like division and subtraction to create new equations with the same solutions. The video also emphasizes simplifying fractions when necessary.

What is the main objective of the video?

• To learn about solving quadratic equations

• To understand how to construct equivalent equations

• To explore the history of algebra

• To practice multiplication tables

Tags

CCSS.6.EE.A.2C

In the first example, what operation is performed first on x = 4?

• Multiply by 7

• Add 7

• Subtract 7

• Divide by 7

Tags

CCSS.HSA.REI.A.1

What is the result of dividing both sides of x = 4 by 7?

• x/7 = 28

• x = 4/7

• x/7 = 4/7

• x = 28

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

How do you simplify the expression 4/7 - 3?

• 4/7 - 21/7

• 4/7 + 3/7

• 4/7 + 21/7

• 4/7 - 3/1

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

What is the least common denominator used to simplify 4/7 - 3?

• 7

• 4

• 3

• 21

Tags

CCSS.HSA.REI.A.1

In the second example, what is the first operation performed on x = 7?

• Divide by 6

• Add 6

• Subtract 6

• Multiply by 6

Tags

CCSS.6.EE.B.7

What is the result of subtracting 6 from both sides of x = 7?

• x - 6 = 13

• x - 6 = 1

• x = 1

• x = 13

Tags

CCSS.HSA.REI.A.1

What is the second operation performed in the second example?

• Multiply by 2

• Add 2

• Divide by 2

• Subtract 2

Tags

CCSS.7.EE.B.4A

What is the final equivalent equation in the second example?

• (x - 6)/2 = 1/2

• x/2 = 1/2

• (x + 6)/2 = 1/2

• x - 6 = 1/2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the common solution for both equations in the second example?

• x = 6

• x = 1

• x = 7

• x = 0

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6