Multiplication Using Traditional Algorithm

The video tutorial demonstrates how to multiply 547 by 362 using a traditional algorithm. It breaks down the process into three main steps: multiplying by 2, 60, and 300, corresponding to the ones, tens, and hundreds place values, respectively. Each step involves detailed calculations, including carrying over values. Finally, the partial products are added together to obtain the final result of 198,014.

What is the first step in solving the multiplication problem of 547 and 362 using a traditional algorithm?

• Write the numbers horizontally

• Write the numbers vertically

• Add the numbers

• Subtract the numbers

Tags

CCSS.4.NBT.B.5

When multiplying 547 by 2, what is the result of 2 times 7?

• 12

• 14

• 18

• 16

Tags

CCSS.4.NBT.B.5

In the multiplication of 547 by 2, what do you do after calculating 2 times 4?

• Add 1

• Add 3

• Add 2

• Add 4

Tags

CCSS.4.NBT.B.5

Why do we place a zero in the ones place when multiplying 547 by 60?

• To adjust for multiplying by 60

• To adjust for multiplying by 100

• To adjust for multiplying by 10

• To adjust for multiplying by 6

Tags

CCSS.4.NBT.B.5

What is the result of 6 times 7 in the multiplication of 547 by 60?

• 36

• 48

• 54

• 42

Tags

CCSS.4.NBT.B.5

When multiplying 547 by 300, why do we place two zeros before starting the multiplication?

• To adjust for multiplying by 3000

• To adjust for multiplying by 30

• To adjust for multiplying by 3

• To adjust for multiplying by 300

Tags

CCSS.4.NBT.B.5

What is the result of 3 times 7 in the multiplication of 547 by 300?

• 18

• 21

• 19

• 20

Tags

CCSS.1.NBT.C.4

CCSS.2.NBT.B.5

In the final addition step, what is the sum of the digits in the tens place?

• 13

• 12

• 11

• 10

Tags

CCSS.2.NBT.B.7

What is the sum of the digits in the thousands place during the final addition?

• 9

• 7

• 6

• 8

Tags

CCSS.5.NBT.B.5

What is the final product of multiplying 547 by 362?

• 198,014

• 199,014

• 200,014

• 201,014

Tags

CCSS.5.NBT.B.5